当组件 0 更改时重置 UIPickerView 第一个组件的值
Reset the value of the 1st component of UIPickerView when component 0 is changed
我不知道如何在更改组件 0 时将 PickerView 的第一个组件中使用的数组重置为组件 0(为了避免由于 indexOutOfRange 可能导致的错误)。
这是我的数据结构
let bananas = ["banana1", "banana2"]
let fruitArray = ["banana1" : ["cherry1","cherry2"], "banana2" : ["cherry1", "cherry2", "cherry3"]]
func numberOfComponents(in pickerView: UIPickerView) -> Int {
return 2
}
func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
if component == 0 {
return bananas.count
}
else {
let selectedBanana = pickerView.selectedRow(inComponent: 0)
return fruitArray[banana[selectedBanana]]!.count
}
}
func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
let selectedBanana = pickerView.selectedRow(inComponent: 0)
let selectedCherry = pickerView.selectedRow(inComponent: 1)
bananaPicked = bananas[selectedBanana]
cherryPicked = fruitArray[bananaPicked]![selectedCherry]
pickerView.reloadAllComponents()
}
func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
if component == 0 {
return bananas[row]
}
else {
let selectedBanana = pickerView.selectedRow(inComponent: 0)
return fruitArray[selectedBanana]![row]
}
}
现在当我(比方说)在 banana2 和 cherry3 中,但我切换到 banana1 时,我收到 indexOutOfRange 错误,因为第一个香蕉数组当然没有第三个项目。我希望每当香蕉行更改为樱桃行重置为 0 时。
__________更新______________
这是我发现的导致崩溃的另一个错误 (indexOutOfRange),我张贴了截图。
更改组件 0 时,将组件 1 中的选定行设置为 0。
此外,无需重新加载所有组件。只有组件 1 需要重新加载。
func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
if component == 0 {
pickerView.selectRow(0, inComponent: 1, animated: false)
}
let selectedBanana = pickerView.selectedRow(inComponent: 0)
let selectedCherry = pickerView.selectedRow(inComponent: 1)
bananaPicked = bananas[selectedBanana]
cherryPicked = fruitArray[bananaPicked]![selectedCherry]
//pickerView.reloadAllComponents()
pickerView.reloadComponent(1)
}
对于第二次崩溃,尝试一些防御性编程来避免崩溃:
func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
if component == 0 {
return bananas[row]
}
else {
let selectedBanana = pickerView.selectedRow(inComponent: 0)
let rowData = fruitArray[bananas[selectedBanana]]!
if rowData.indices.contains(row) {
return rowData[row]
} else {
return nil
}
}
}
我不知道如何在更改组件 0 时将 PickerView 的第一个组件中使用的数组重置为组件 0(为了避免由于 indexOutOfRange 可能导致的错误)。
这是我的数据结构
let bananas = ["banana1", "banana2"]
let fruitArray = ["banana1" : ["cherry1","cherry2"], "banana2" : ["cherry1", "cherry2", "cherry3"]]
func numberOfComponents(in pickerView: UIPickerView) -> Int {
return 2
}
func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
if component == 0 {
return bananas.count
}
else {
let selectedBanana = pickerView.selectedRow(inComponent: 0)
return fruitArray[banana[selectedBanana]]!.count
}
}
func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
let selectedBanana = pickerView.selectedRow(inComponent: 0)
let selectedCherry = pickerView.selectedRow(inComponent: 1)
bananaPicked = bananas[selectedBanana]
cherryPicked = fruitArray[bananaPicked]![selectedCherry]
pickerView.reloadAllComponents()
}
func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
if component == 0 {
return bananas[row]
}
else {
let selectedBanana = pickerView.selectedRow(inComponent: 0)
return fruitArray[selectedBanana]![row]
}
}
现在当我(比方说)在 banana2 和 cherry3 中,但我切换到 banana1 时,我收到 indexOutOfRange 错误,因为第一个香蕉数组当然没有第三个项目。我希望每当香蕉行更改为樱桃行重置为 0 时。
__________更新______________ 这是我发现的导致崩溃的另一个错误 (indexOutOfRange),我张贴了截图。
更改组件 0 时,将组件 1 中的选定行设置为 0。
此外,无需重新加载所有组件。只有组件 1 需要重新加载。
func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
if component == 0 {
pickerView.selectRow(0, inComponent: 1, animated: false)
}
let selectedBanana = pickerView.selectedRow(inComponent: 0)
let selectedCherry = pickerView.selectedRow(inComponent: 1)
bananaPicked = bananas[selectedBanana]
cherryPicked = fruitArray[bananaPicked]![selectedCherry]
//pickerView.reloadAllComponents()
pickerView.reloadComponent(1)
}
对于第二次崩溃,尝试一些防御性编程来避免崩溃:
func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
if component == 0 {
return bananas[row]
}
else {
let selectedBanana = pickerView.selectedRow(inComponent: 0)
let rowData = fruitArray[bananas[selectedBanana]]!
if rowData.indices.contains(row) {
return rowData[row]
} else {
return nil
}
}
}