charmap 编解码器无法解码 python 中 gzip 文件的字节错误

Question

我正在尝试使用 python 发送一封包含 gzip 格式文件作为附件的电子邮件。

但是我在尝试发送文件时遇到错误。这是我得到的异常：

Exception:  'charmap' codec can't decode byte 0x90 in position 75: character maps to <undefined>

这就是我在代码中所做的：

import gzip
destination = 'path/to/file'
to_addr = input("Enter the recipient's email address: ")
from_addr = 'cloudops@noreply.company.com'
subject = "Commpany AWS Billing Info "
content = "email to the user about the file"
msg = MIMEMultipart()
msg['From'] = from_addr
msg['To'] = to_addr
msg['Subject'] = subject
body = MIMEText(content, 'html')
msg.attach(body)
server = smtplib.SMTP('smtpout.us.companyworld.company.com', 25)
filename = destination
try:
    with open(filename, 'r') as f:
        part = MIMEApplication(f.read(), Name=basename(filename))
        part['Content-Disposition'] = 'attachment; filename="{}"'.format(basename(filename))
        msg.attach(part)
        server.send_message(msg, from_addr=from_addr, to_addrs=[to_addr])
    print("Email was sent to: %s" %  to_addr)
except Exception as e:
    print("Exception: ", e)
    print("Email was not sent.")

我尝试发送的文件是在这些行中的另一个函数中创建的：

    import pandas
    read_sql = 'select * from somedb'
    mydb = mysql.connector.connect(user='x', password='x',host='x',database='aws_bill')
    results = pandas.read_sql_query(read_sql, mydb)
    results.to_csv(destination, index=False, encoding='utf8', compression='gzip')

如何更正此问题并发送附件？

Answer 1

问题出在这一行：

with open(filename, 'r') as f:

您正在以文本模式打开 gzip 文件，因此 Python 正在尝试对其进行解码； gzip 文件应以 binary 模式打开，如下所示：

with open(filename, 'rb') as f:

charmap 编解码器无法解码 python 中 gzip 文件的字节错误

charmap codec can't decode byte error with gzipped file in python

python

email

gzip

smtplib