asyncio.Semaphore RuntimeError: Task got Future attached to a different loop
asyncio.Semaphore RuntimeError: Task got Future attached to a different loop
当我 运行 这个代码在 Python 3.7:
import asyncio
sem = asyncio.Semaphore(2)
async def work():
async with sem:
print('working')
await asyncio.sleep(1)
async def main():
await asyncio.gather(work(), work(), work())
asyncio.run(main())
它因运行时错误而失败:
$ python3 demo.py
working
working
Traceback (most recent call last):
File "demo.py", line 13, in <module>
asyncio.run(main())
File "/opt/local/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/asyncio/runners.py", line 43, in run
return loop.run_until_complete(main)
File "/opt/local/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/asyncio/base_events.py", line 584, in run_until_complete
return future.result()
File "demo.py", line 11, in main
await asyncio.gather(work(), work(), work())
File "demo.py", line 6, in work
async with sem:
File "/opt/local/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/asyncio/locks.py", line 92, in __aenter__
await self.acquire()
File "/opt/local/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/asyncio/locks.py", line 474, in acquire
await fut
RuntimeError: Task <Task pending coro=<work() running at demo.py:6> cb=[gather.<locals>._done_callback() at /opt/local/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/asyncio/tasks.py:664]> got Future <Future pending> attached to a different loop
这是因为 Semaphore 构造函数设置了它的 _loop
属性 – 在 asyncio/locks.py:
class Semaphore(_ContextManagerMixin):
def __init__(self, value=1, *, loop=None):
if value < 0:
raise ValueError("Semaphore initial value must be >= 0")
self._value = value
self._waiters = collections.deque()
if loop is not None:
self._loop = loop
else:
self._loop = events.get_event_loop()
但是 asyncio.run()
开始了一个全新的循环——在 asyncio/runners.py 中,文档中也提到了它:
def run(main, *, debug=False):
if events._get_running_loop() is not None:
raise RuntimeError(
"asyncio.run() cannot be called from a running event loop")
if not coroutines.iscoroutine(main):
raise ValueError("a coroutine was expected, got {!r}".format(main))
loop = events.new_event_loop()
...
Semaphore
在 asyncio.run()
之外启动会获取异步“默认”循环,因此不能与使用 asyncio.run()
.
创建的事件循环一起使用
解决方案
从 asyncio.run()
调用的代码启动 Semaphore
。你必须将它们传递到正确的地方,有更多的可能性如何做到这一点,例如你可以使用 contextvars,但我只举最简单的例子:
import asyncio
async def work(sem):
async with sem:
print('working')
await asyncio.sleep(1)
async def main():
sem = asyncio.Semaphore(2)
await asyncio.gather(work(sem), work(sem), work(sem))
asyncio.run(main())
asyncio.Lock
、asyncio.Event
和 asyncio.Condition
可能也存在同样的问题(和解决方案)。
当我 运行 这个代码在 Python 3.7:
import asyncio
sem = asyncio.Semaphore(2)
async def work():
async with sem:
print('working')
await asyncio.sleep(1)
async def main():
await asyncio.gather(work(), work(), work())
asyncio.run(main())
它因运行时错误而失败:
$ python3 demo.py
working
working
Traceback (most recent call last):
File "demo.py", line 13, in <module>
asyncio.run(main())
File "/opt/local/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/asyncio/runners.py", line 43, in run
return loop.run_until_complete(main)
File "/opt/local/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/asyncio/base_events.py", line 584, in run_until_complete
return future.result()
File "demo.py", line 11, in main
await asyncio.gather(work(), work(), work())
File "demo.py", line 6, in work
async with sem:
File "/opt/local/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/asyncio/locks.py", line 92, in __aenter__
await self.acquire()
File "/opt/local/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/asyncio/locks.py", line 474, in acquire
await fut
RuntimeError: Task <Task pending coro=<work() running at demo.py:6> cb=[gather.<locals>._done_callback() at /opt/local/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/asyncio/tasks.py:664]> got Future <Future pending> attached to a different loop
这是因为 Semaphore 构造函数设置了它的 _loop
属性 – 在 asyncio/locks.py:
class Semaphore(_ContextManagerMixin):
def __init__(self, value=1, *, loop=None):
if value < 0:
raise ValueError("Semaphore initial value must be >= 0")
self._value = value
self._waiters = collections.deque()
if loop is not None:
self._loop = loop
else:
self._loop = events.get_event_loop()
但是 asyncio.run()
开始了一个全新的循环——在 asyncio/runners.py 中,文档中也提到了它:
def run(main, *, debug=False):
if events._get_running_loop() is not None:
raise RuntimeError(
"asyncio.run() cannot be called from a running event loop")
if not coroutines.iscoroutine(main):
raise ValueError("a coroutine was expected, got {!r}".format(main))
loop = events.new_event_loop()
...
Semaphore
在 asyncio.run()
之外启动会获取异步“默认”循环,因此不能与使用 asyncio.run()
.
解决方案
从 asyncio.run()
调用的代码启动 Semaphore
。你必须将它们传递到正确的地方,有更多的可能性如何做到这一点,例如你可以使用 contextvars,但我只举最简单的例子:
import asyncio
async def work(sem):
async with sem:
print('working')
await asyncio.sleep(1)
async def main():
sem = asyncio.Semaphore(2)
await asyncio.gather(work(sem), work(sem), work(sem))
asyncio.run(main())
asyncio.Lock
、asyncio.Event
和 asyncio.Condition
可能也存在同样的问题(和解决方案)。