如何解析 String.format 向 int 添加 0
How to Parse String.format added 0's to int
我想生成随机的国民身份证号码,当我用 String.format() 添加 0 来填充数字时,我无法将其解析回 int
public class NinGenerator {
public static void Generator(sex name){ // sex is enum
Random rand = new Random();
int year = rand.nextInt(60) + 40; // For starting at year 40
int month, day, finalNumbers;
month = rand.nextInt(12) + 1;
if(name == sex.FEMALE){ // In case of female
month += 50;
}
switch(month){ // For max number of days to match given month
```
case 1:
case 3:
day = rand.nextInt(30) + 1;
```
}
finalNumbers = rand.nextInt(9999) + 1; // last set of numbers
String nin = FillZeroes(year, 2) + FillZeroes(month, 2) + FillZeroes(day, 2) + FillZeroes(finalNumbers, 4); // Merging it into string
// Here occurs error
int ninInt = Integer.parseInt(nin); // Parsing it into number
while(ninInt % 11 != 0){ // Whole number has to be divisble by 11 without remainder
ninInt++;
}
System.out.println("National identification number: " + ninInt);
}
public static String FillZeroes(int number, int digits){ // For number to correspond with number of digits - filling int with zeros
String text = String.valueOf(number);
if(text.length() < digits){
while(text.length() != digits){
text = String.format("%d1", number);
}
}
return text;
}
}
我想生成能被11整除的10位数字没有提醒,编译器总是在解析的那一行产生错误
我测试了你的代码,我相信你已经达到了 int 可以达到的极限。如果您尝试将“2147483647”作为您的 nin 值,它将 运行,但是一旦您转到“2147483648”,您将得到相同的错误。如果你想解决这个问题,你可能必须使用 long 或 double 等数据类型,具体取决于你想用它做什么。
Here is a link showing the different datatypes and their ranges.
您的 FillZeroes() 函数可以简单地是:
public static String FillZeroes(int number, int digits)
{
String format = "d" + digits.ToString();
return number.ToString(format);
}
我想生成随机的国民身份证号码,当我用 String.format() 添加 0 来填充数字时,我无法将其解析回 int
public class NinGenerator {
public static void Generator(sex name){ // sex is enum
Random rand = new Random();
int year = rand.nextInt(60) + 40; // For starting at year 40
int month, day, finalNumbers;
month = rand.nextInt(12) + 1;
if(name == sex.FEMALE){ // In case of female
month += 50;
}
switch(month){ // For max number of days to match given month
```
case 1:
case 3:
day = rand.nextInt(30) + 1;
```
}
finalNumbers = rand.nextInt(9999) + 1; // last set of numbers
String nin = FillZeroes(year, 2) + FillZeroes(month, 2) + FillZeroes(day, 2) + FillZeroes(finalNumbers, 4); // Merging it into string
// Here occurs error
int ninInt = Integer.parseInt(nin); // Parsing it into number
while(ninInt % 11 != 0){ // Whole number has to be divisble by 11 without remainder
ninInt++;
}
System.out.println("National identification number: " + ninInt);
}
public static String FillZeroes(int number, int digits){ // For number to correspond with number of digits - filling int with zeros
String text = String.valueOf(number);
if(text.length() < digits){
while(text.length() != digits){
text = String.format("%d1", number);
}
}
return text;
}
}
我想生成能被11整除的10位数字没有提醒,编译器总是在解析的那一行产生错误
我测试了你的代码,我相信你已经达到了 int 可以达到的极限。如果您尝试将“2147483647”作为您的 nin 值,它将 运行,但是一旦您转到“2147483648”,您将得到相同的错误。如果你想解决这个问题,你可能必须使用 long 或 double 等数据类型,具体取决于你想用它做什么。
Here is a link showing the different datatypes and their ranges.
您的 FillZeroes() 函数可以简单地是:
public static String FillZeroes(int number, int digits)
{
String format = "d" + digits.ToString();
return number.ToString(format);
}