排序 HTML Table,通过 JQuery 附加
Sort HTML Table, that gets appended via JQuery
您好,我正在尝试使用 Tablesorter(https://github.com/christianbach/tablesorter) 对我通过 JQuery.appends 生成的 table 进行排序。这是我的代码的样子:
$(document).ready(function() {
*Lotsa more code .....*
$.get("../skillqueue",{keyid: keyid, charid: charid},function(xmlskillqueue){
console.log("XML Skillqueue");
console.log(xmlskillqueue);
//Variables for
var rowsets = xmlskillqueue.getElementsByTagName("rowset");
var skillrows;
for(var i = 0; i < rowsets.length; i++){
if(rowsets[i].getAttribute("name") == "skillqueue"){
skillrows = rowsets[i].getElementsByTagName("row");
}
}
//Defines Table Headers
$("#tableskillqueuelist").append(
"<thead>" +
"<tr>" +
"<th>Order: </th> "+
"<th>Skill Name: </th> "+
"<th>Training to: </th> "+
"<th>Starts:</th> "+
"<th>Ends:</th> "+
"</tr> "+
"</thead>"+
"<tbody>"
);
for(var i = 0; i < skillrows.length; i++){
(function(i, skillrows) {
$.get("../getitemname", {itemid:skillrows.getAttribute("typeID")},function(itemname){
$("#tableskillqueuelist").append(
"<tr> " +
"<td>" + skillrows.getAttribute("queuePosition") + ". " +
"<td>" + itemname + "</td>" +
"<td>" + "|Train to: " + skillrows.getAttribute("level") + "</td>" +
"<td>" + "|Training Starts: " + skillrows.getAttribute("startTime") + "</td>" +
"<td>" + "|Training Ends: " + skillrows.getAttribute("endTime") + "<td>" +
"</tr>"
);
})
})(i, skillrows[i]);
}
//Ends the table body
$("#tableskillqueuelist").append("</tbody>");
});
});
现在我想知道我需要做什么才能成功 运行 $("#tableskillqueuelist").tablesorter();方法。因为似乎每当我尝试 运行 它时,#tableskillqueuelist 似乎是空的。
您需要告诉 table 排序器您已经更改了数据并希望通过触发事件对其进行排序。
来自文档的示例:http://tablesorter.com/docs/example-ajax.html
$("table").tablesorter();
$("#ajax-append").click(function() {
$.get("assets/ajax-content.html", function(html) {
// append the "ajax'd" data to the table body
$("table tbody").append(html);
// let the plugin know that we made a update
$("table").trigger("update");
// set sorting column and direction, this will sort on the first and third column
var sorting = [[2,1],[0,0]];
// sort on the first column
$("table").trigger("sorton",[sorting]);
});
return false;
});
HTH
您好,我正在尝试使用 Tablesorter(https://github.com/christianbach/tablesorter) 对我通过 JQuery.appends 生成的 table 进行排序。这是我的代码的样子:
$(document).ready(function() {
*Lotsa more code .....*
$.get("../skillqueue",{keyid: keyid, charid: charid},function(xmlskillqueue){
console.log("XML Skillqueue");
console.log(xmlskillqueue);
//Variables for
var rowsets = xmlskillqueue.getElementsByTagName("rowset");
var skillrows;
for(var i = 0; i < rowsets.length; i++){
if(rowsets[i].getAttribute("name") == "skillqueue"){
skillrows = rowsets[i].getElementsByTagName("row");
}
}
//Defines Table Headers
$("#tableskillqueuelist").append(
"<thead>" +
"<tr>" +
"<th>Order: </th> "+
"<th>Skill Name: </th> "+
"<th>Training to: </th> "+
"<th>Starts:</th> "+
"<th>Ends:</th> "+
"</tr> "+
"</thead>"+
"<tbody>"
);
for(var i = 0; i < skillrows.length; i++){
(function(i, skillrows) {
$.get("../getitemname", {itemid:skillrows.getAttribute("typeID")},function(itemname){
$("#tableskillqueuelist").append(
"<tr> " +
"<td>" + skillrows.getAttribute("queuePosition") + ". " +
"<td>" + itemname + "</td>" +
"<td>" + "|Train to: " + skillrows.getAttribute("level") + "</td>" +
"<td>" + "|Training Starts: " + skillrows.getAttribute("startTime") + "</td>" +
"<td>" + "|Training Ends: " + skillrows.getAttribute("endTime") + "<td>" +
"</tr>"
);
})
})(i, skillrows[i]);
}
//Ends the table body
$("#tableskillqueuelist").append("</tbody>");
});
});
现在我想知道我需要做什么才能成功 运行 $("#tableskillqueuelist").tablesorter();方法。因为似乎每当我尝试 运行 它时,#tableskillqueuelist 似乎是空的。
您需要告诉 table 排序器您已经更改了数据并希望通过触发事件对其进行排序。
来自文档的示例:http://tablesorter.com/docs/example-ajax.html
$("table").tablesorter();
$("#ajax-append").click(function() {
$.get("assets/ajax-content.html", function(html) {
// append the "ajax'd" data to the table body
$("table tbody").append(html);
// let the plugin know that we made a update
$("table").trigger("update");
// set sorting column and direction, this will sort on the first and third column
var sorting = [[2,1],[0,0]];
// sort on the first column
$("table").trigger("sorton",[sorting]);
});
return false;
});
HTH