从 json 响应中删除 unicode 字符串和空格

Question

我正在调用一个网络服务，它给我 Json 响应。这是代码

URL url = new URL(strUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
...
//get response text
BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream(),"UTF-8"));           
StringBuffer response = new StringBuffer();
while ((respText = br.readLine()) != null) {                
    response.append(respText);
}
br.close(); 
retValue = response.toString();

问题是响应如下

"{\u000d\u000a  \"groups\": [\u000d\u000a    {\u000d\u000a      \"signingGroupId\": \"323793\",\u000d\u000a      \"groupName\": \"1440 Signing Group 1\",\u000d\u000a      \"groupType\": \"sharedSigningGroup\",\u000d\u000a      \"created\": \"3\/27\/2019 6:08:34 AM\",\u000d\u000a      \"createdBy\": \"ABC Software\",\u000d\u000a      \"modified\": \"4\/1\/2019 6:40:45 AM\",\u000d\u000a      \"modifiedBy\": \"Corner O'Brien\"\u000d\u000a    },\u000d\u000a    {\u000d\u000a      \"signingGroupId\": \"323794\",\u000d\u000a      \"groupName\": \"1440 Another Group\",\u000d\u000a      \"groupType\": \"sharedSigningGroup\",\u000d\u000a      \"created\": \"3\/27\/2019 6:14:52 AM\",\u000d\u000a      \"createdBy\": \"XYZ Software\",\u000d\u000a      \"modified\": \"3\/27\/2019 6:16:37 AM\",\u000d\u000a      \"modifiedBy\": \"XYZ Software\"\u000d\u000a    }\u000d\u000a  ]\u000d\u000a}"

我想从上面的回复中做出这样的回复

"{"groups":[{"signingGroupId": "323793","groupName": "1440 Signing Group 1","groupType": "sharedSigningGroup","created": "3/27/2019 6:08:34 AM","createdBy": "ABC Software","modified": "4/1/2019 6:40:45 AM","modifiedBy": "John O'Brien"},{"signingGroupId": "323794","groupName": "1440 Another Group","groupType": "sharedSigningGroup","created": "3/27/2019 6:14:52 AM","createdBy": "ABC Software","modified": "3/27/2019 6:16:37 AM","modifiedBy": "ABC Software"}]}"

也就是把后面的\u000d\u000a和spaces全部去掉。但不要从任何 Json 属性.

中删除 space

我试过了

retValue = retValue.replace("\u000d\u000a", "");
retValue = retValue.replace("\", "");

这给了我

"{  "groups": [    {      "signingGroupId": "323793",      "groupName": "1440 Signing Group 1",      "groupType": "sharedSigningGroup",      "created": "3/27/2019 6:08:34 AM",      "createdBy": "ABC Software",      "modified": "4/1/2019 6:40:45 AM",      "modifiedBy": "John O'Brien"    },    {      "signingGroupId": "323794",      "groupName": "1440 Another Group",      "groupType": "sharedSigningGroup",      "created": "3/27/2019 6:14:52 AM",      "createdBy": "XYZ Software",      "modified": "3/27/2019 6:16:37 AM",      "modifiedBy": "XYZ Software"    }  ]}"

但是还有space。现在如果我使用

String replcaedNewLineAndSpaces = retValue.replaceAll("[ \t]+", "");

这一行有问题，它还从 Json 属性中删除了 spaces。

"{"groups":[{"signingGroupId":"323793","groupName":"1440SigningGroup1","groupType":"sharedSigningGroup","created":"3/27/20196:08:34AM","createdBy":"ABCSoftware","modified":"4/1/20196:40:45AM","modifiedBy":"JohnO'Brien"},{"signingGroupId":"323794","groupName":"1440AnotherGroup","groupType":"sharedSigningGroup","created":"3/27/20196:14:52AM","createdBy":"XYZSoftware","modified":"3/27/20196:16:37AM","modifiedBy":"XYZSoftware"}]}"

查看 "groupName": "1440 Signing Group 1" 的 groupName。现在变成 1440SigningGroup1。其他属性也类似。

有没有它保持 Json 字符串不变，但删除它后面的 \u000d\u000a 和 spaces。所以最后的回复变成

"{"groups":[{"signingGroupId": "323793","groupName": "1440 Signing Group 1","groupType": "sharedSigningGroup","created": "3/27/2019 6:08:34 AM","createdBy": "ABC Software","modified": "4/1/2019 6:40:45 AM","modifiedBy": "John O'Brien"},{"signingGroupId": "323794","groupName": "1440 Another Group","groupType": "sharedSigningGroup","created": "3/27/2019 6:14:52 AM","createdBy": "ABC Software","modified": "3/27/2019 6:16:37 AM","modifiedBy": "ABC Software"}]}"

谢谢

Answer 1

如评论中所述，创建 POJO class 并解析 JSON 将是最佳且安全的。（我觉得最常用的库是GSon library）

但是，如果您坚持要删除空格，请使用简单的正则表达式：

retValue.replaceAll("\\u000d\\u000a\s*", "")

这将替换所有以 \u000d\u000a 开头后跟 0 个无限空格的字符串。

从 json 响应中删除 unicode 字符串和空格

Remove unicode string and spaces from json response

java

regex

jackson

httpurlconnection