我们如何在每日报告的同一行中获取今天的值和最近 7 天的值？

Question

我在 SQL Server 2008 R2 中有一个 table，有 3 列，Name、Date 和 Today's values。我可以在报告中轻松显示，但我们还需要在同一报告中查看 "Last 7 days total" 值。我的意思是每一行都应该表示为名称、日期、今天的价值和过去 7 天的总计。

能帮忙查询一下吗？

Answer 1

SELECT 
    t.Name, t.Date, t.Value, 
    (SELECT SUM(s.Value) 
     FROM your_table s 
     WHERE s.date <= t.date 
       AND s.date > DATEADD(DAY, -7, t.date
    ) AS last_7day_value
FROM 
    your_table t
WHERE 
    t.date BETWEEN @start_date AND @end_date;

Answer 2

由于您不能使用排序的窗口聚合来生成总计，因此您可以通过自 join 和 [=14 在没有子 select 或非等值连接逻辑的情况下执行此操作=]:

declare @t table(ValueName varchar(10),ValueDate date, ValueAmount int);
insert into @t values
 ('Name 1','20190101',4)
,('Name 1','20190102',3)
,('Name 1','20190103',8)
,('Name 1','20190104',6)
,('Name 1','20190105',9)
,('Name 1','20190106',6)
,('Name 1','20190107',3)
,('Name 1','20190108',2)
,('Name 1','20190109',1)
,('Name 2','20190101',3)
,('Name 2','20190102',7)
,('Name 2','20190103',6)
,('Name 2','20190104',8)
,('Name 2','20190105',8)
,('Name 2','20190106',7)
,('Name 2','20190107',6)
,('Name 2','20190108',9)
,('Name 2','20190109',3);

select t.ValueName
      ,t.ValueDate
      ,t.ValueAmount
      ,t.ValueAmount + isnull(sum(p.ValueAmount),0) as SevenDayTotal
from @t as t
    cross apply(values(dateadd(day,-1,t.ValueDate))
                     ,(dateadd(day,-2,t.ValueDate))
                     ,(dateadd(day,-3,t.ValueDate))
                     ,(dateadd(day,-4,t.ValueDate))
                     ,(dateadd(day,-5,t.ValueDate))
                     ,(dateadd(day,-6,t.ValueDate))
                     ) as d(d)
    left join @t as p
        on t.ValueName = p.ValueName
            and p.ValueDate = d.d
group by t.ValueName
      ,t.ValueDate
      ,t.ValueAmount
order by t.ValueName
      ,t.ValueDate;

输出

+-----------+------------+-------------+---------------+
| ValueName | ValueDate  | ValueAmount | SevenDayTotal |
+-----------+------------+-------------+---------------+
| Name 1    | 2019-01-01 |           4 |             4 |
| Name 1    | 2019-01-02 |           3 |             7 |
| Name 1    | 2019-01-03 |           8 |            15 |
| Name 1    | 2019-01-04 |           6 |            21 |
| Name 1    | 2019-01-05 |           9 |            30 |
| Name 1    | 2019-01-06 |           6 |            36 |
| Name 1    | 2019-01-07 |           3 |            39 |
| Name 1    | 2019-01-08 |           2 |            37 |
| Name 1    | 2019-01-09 |           1 |            35 |
| Name 2    | 2019-01-01 |           3 |             3 |
| Name 2    | 2019-01-02 |           7 |            10 |
| Name 2    | 2019-01-03 |           6 |            16 |
| Name 2    | 2019-01-04 |           8 |            24 |
| Name 2    | 2019-01-05 |           8 |            32 |
| Name 2    | 2019-01-06 |           7 |            39 |
| Name 2    | 2019-01-07 |           6 |            45 |
| Name 2    | 2019-01-08 |           9 |            51 |
| Name 2    | 2019-01-09 |           3 |            47 |
+-----------+------------+-------------+---------------+

我们如何在每日报告的同一行中获取今天的值和最近 7 天的值？

How do we get today's value and last 7 days value in the same row in the daily report?

sql

sql-server-2008-r2

输出