通过标签名获取 xml 个元素

Question

我在这里看到了几乎所有关于此问题的问题，但 none 是相关的。

$employees = simplexml_load_string($response)->c->q[1]['v'];

$employees = SimpleXML 对象:

<?xml version="1.0" encoding="utf-8" ?>
<rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation = "Articles_Schema.xsd" >
    <row id="1">
        <EmployeeID>
            <![CDATA[123]]>
        </EmployeeID>
        <EmplopyeeName>
            <![CDATA[John Doe]]>
        </EmplopyeeName>
    </row>
    <row id="2">
       <EmployeeID>
            <![CDATA[456]]>
        </EmployeeID>
        <EmplopyeeName>
            <![CDATA[Jack Mill]]>
        </EmplopyeeName>
    </row>
</rows>

我想检索所有员工（如果找到）。

我尝试使用以下方式访问它们：

$employees->children() [空数组]
$employees->rows [空数组]
$employees->row [空数组]
$employees->xpath('//rows') [空数组]
$employees->xpath('//row') [空数组]
$employees->registerXPathNamespace('x', 'http://www.w3.org/2001/XMLSchema-instance'); $employees->xpath('//x:row') [空数组]

var_dump($employees->getName()); //returns "v"

var_dump($employees->getNamespaces()); //returns NULL

var_dump($employees); Returns:

object(SimpleXMLElement)#26 (1) {
  [0]=>
  string(xxx) "
<?xml version="1.0" encoding="utf-8" ?>
    <rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation = "Articles_Schema.xsd" >
        <row id="1">
            <EmployeeID>
                <![CDATA[123]]>
            </EmployeeID>
            <EmplopyeeName>
                <![CDATA[John Doe]]>
            </EmplopyeeName>
        </row>
        <row id="2">
           <EmployeeID>
                <![CDATA[456]]>
            </EmployeeID>
            <EmplopyeeName>
                <![CDATA[Jack Mill]]>
            </EmplopyeeName>
        </row>
    </rows>"
}

有人可以指出可能导致问题的原因吗？

Answer 1

这对我有用：

<?php

$employees =<<< EMP
<?xml version="1.0" encoding="utf-8" ?>
<rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation = "Articles_Schema.xsd" >
    <row id="1">
        <EmployeeID>
            <![CDATA[123]]>
        </EmployeeID>
        <EmplopyeeName>
            <![CDATA[John Doe]]>
        </EmplopyeeName>
    </row>
    <row id="2">
       <EmployeeID>
            <![CDATA[456]]>
        </EmployeeID>
        <EmplopyeeName>
            <![CDATA[Jack Mill]]>
        </EmplopyeeName>
    </row>
</rows>
EMP;

$employees = simplexml_load_string($employees);
foreach($employees->row as $row)
{
   print((string) $row->EmployeeID);
   print((string) $row->EmplopyeeName);
}

针对您的情况可以尝试的东西：

$employeeXml = simplexml_load_string((string) $employees);
foreach($employeeXml->row as $row)
{
   print((string) $row->EmployeeID);
   print((string) $row->EmplopyeeName);
}

Answer 2

你可以这样处理

$xml = <<< EMP
<?xml version="1.0" encoding="utf-8" ?>
<rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation = "Articles_Schema.xsd" >
<row id="1">
    <EmployeeID>
        <![CDATA[123]]>
    </EmployeeID>
    <EmplopyeeName>
        <![CDATA[John Doe]]>
    </EmplopyeeName>
</row>
 <row id="2">
   <EmployeeID>
        <![CDATA[456]]>
    </EmployeeID>
    <EmplopyeeName>
        <![CDATA[Jack Mill]]>
    </EmplopyeeName>
 </row>
</rows>
EMP;
$xmlToArray = json_decode(json_encode((array)simplexml_load_string($xml,null,LIBXML_NOCDATA)),true);
foreach($xmlToArray['row'] as $row){
 echo trim($row['EmployeeID']).'---'.trim($row['EmplopyeeName']);
}

DEMO LINK

通过标签名获取 xml 个元素

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