Swift: Mandrill POST 问题

Question

我正在尝试通过 Mandrill API 发送电子邮件。我在下面找到 swift 代码 here 用于 JSON HTTP POST 方法：

func createRequest(myUrl : String, type : String, params : NSDictionary?, completion : (AnyObject?, NSError?)->Void ){
        var url = NSURL(string: myUrl)
        var request = NSMutableURLRequest(URL: url!, cachePolicy: NSURLRequestCachePolicy.UseProtocolCachePolicy, timeoutInterval: 60.0)
        if params != nil {
            var data = NSJSONSerialization.dataWithJSONObject(params!, options: NSJSONWritingOptions.PrettyPrinted, error: nil)
            request.setValue("\(data!.length)", forHTTPHeaderField: "Content-Length")
            request.HTTPBody = data
        }
        request.setValue("application/json", forHTTPHeaderField:"Content-type")
        request.setValue("application/json", forHTTPHeaderField: "Accept")
        request.HTTPMethod = type
        NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue(),
            completionHandler: {(response: NSURLResponse!, data: NSData!, error: NSError!) in
                var returnedObject : AnyObject! = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableLeaves, error: nil)
                completion(returnedObject,error)
        })
    }

现在我这样设置 url 和参数：

let url = "https://mandrillapp.com/api/1.0/messages/send.json"
let to = ["email" : "xyz@gmail.com"]
let message = [
    "from_email" : "noreply@abc.com",
    "from_name" : "abc",
    "subject" : "Message through abc",
    "text" : "sample message",
    "to" : to
]
let params = [
    "key": "myKey",
    "message" : message
]

然后我这样调用这个函数：

createRequest(url, type: "POST", params: params, completion: {(returnedObject : AnyObject?, error : NSError?)in
    if (returnedObject != nil) {
        println("data = \(returnedObject)")
    }
})

但我得到错误：

data = Optional({
   code = "-2";
   message = "Validation error: {\"message\":{\"to\":[\"Please enter an array\"]}}";
   name = ValidationError;
   status = error;
})

我做错了什么？

Answer 1

我不知道你用的是什么框架（甚至编程语言），但是回复好像很清楚。

事情是这样的：

let to = ["email" : "xyz@gmail.com"]

这对我来说显然不像数组，更像是字典（或语言中的等效项）。我认为以下方法可行：

let to = ["xyz@gmail.com"]

编辑

也许，这会：

"to": [ { "email": "recipient.email@example.com", "name": "Recipient Name", "type": "to" } ]

我的下一个猜测是名称和类型不是可选的..并且 "to" 字段需要一个字典项数组。

Answer 2

终于！！！我自己想出来了。

let to = ["email" : "kashif.izhar@gmail.com"]

应该是

let to = [["email" : "kashif.izhar@gmail.com"]]

希望对大家有所帮助

Swift: Mandrill POST 问题

Swift: Mandrill POST Issue

json

ios

mandrill

swift