Sequelize - 如何 add/upsert 具有软删除行相同主键的行

Question

我正在使用 sequelize ORM。我有一个 table 的模型，我们通过 paranoid: true.

启用了软删除

问题： 有没有办法做一个更新插入，如果对象已经存在于 table 但被软删除，它只会清除 deletedAt专栏?

示例设置：model.js

const Sequelize = require('sequelize')
const sequelize = new Sequelize(
  dbName,
  username,
  password,
  {
    host,
    dialect: 'mysql',
    port
  }
)

const model =  sequelize.define(
  'sample_table',
  {
    uid: {
      type: Sequelize.STRING(60),
      allowNull: false
      primaryKey: true
    },
    deletedAt: {
      type: Sequelize.Date,
      allowNull: true,
      default: null
    }
  },
  {
    tableName: 'sample_table'
    deletedAt: true,
    paranoid: true
  }
)

示例用法：

const model = require('./model.js')

(async () => {
  const myModel = await model.create({
    uid: 'sample-uid'
  })

  await myModel.destroy()

  // error is encountered because uid already exists
  await model.create({
    uid: 'sample-uid'
  })
})()

Answer 1

是的，但您应该手动执行（例如，添加 catch 以创建方法并使用 .restore() 清除 deletedAt 列）。

或者您可以在 uid + deletedAt 上添加一个主键，您的代码应该可以正常运行。

const model = require('./model.js')

(async () => {
  const myModel = await model.create({
    uid: 'sample-uid'
  })

  await myModel.destroy()

  // if primary key uid and deletedAt then no error here
  await model.create({
    uid: 'sample-uid'
  })
})()

Sequelize - 如何 add/upsert 具有软删除行相同主键的行

Sequelize - How to add/upsert row with same primary key of soft deleted row

upsert

soft-delete

sequelize.js