如何读取上一个命令的输出，然后继续执行下一个命令

Question

我想写一个脚本，只有在上一个命令成功时才会执行下一个命令。

作为脚本的一部分，我正在尝试添加文件。添加文件的命令成功执行后，我会收到如下消息：

May 10, 2019 5:57:12 AM com.ibm.ws.jmx.connector.client.rest.internal.RESTMBeanServerConnection findInitialEndpoint
INFO: CWWKX0230I: The collective member opened JMX client to the collective controller: ncr-aus-e171.corp.wayport.net:9081
May 10, 2019 5:57:12 AM com.ibm.ws.jmx.connector.client.rest.internal.RESTMBeanServerConnection findInitialEndpoint
INFO: CWWKX0230I: The collective member opened JMX client to the collective controller: ncr-aus-e171.corp.wayport.net:9081
Successfully pushed policy to server

收到 "Successfully pushed policy to server" 消息后，我希望脚本推送下一个文件。（以此类推 50 个不同的文件）

谁能告诉我如何实现它？

Answer 1

试试这个：

#!/bin/bash
Commands=(
  "command1 parameter1 parameter2"
  "command2 parameter1"
  "command3 parameter1 parameter2 parameter3"
)

tmplog=$(mktemp)
for cmd in "${Commands[@]}"; do
   echo "$cmd"
   $cmd >"$tmplog"
   tail -1 "$tmplog" | grep -v "^Successfully" && break
done
rm "$tmplog"

如何读取上一个命令的输出，然后继续执行下一个命令

How to read the output of previous command and then proceed to the next command

linux

shell

scripting

tivoli