java.sql.SQLSyntaxErrorException: 没有这样的列:id

java.sql.SQLSyntaxErrorException: No such column: id

java.sql.SQLSyntaxErrorException: No such column: id

当 table 已经包含列 id

我正在尝试使用来自存储库 class 的 MariaDB SQL 中 运行 具有预期结果的以下本机 SQL 查询:

SELECT name
FROM table1 t1
WHERE t1.table2_id IN (
  SELECT id
  FROM table2 t2
  WHERE t2.column1_number = 1 AND
        t2.id IS NOT NULL
  )
ORDER BY t1.name 

实体class如下:


@Entity
@Table(name = "table1")
public class Table1 {

    @Column(nullable = false)
    private String name;

    @Column(nullable = false)
    private Integer number;

    @ManyToOne
    @JoinColumn(name = "table2_id")
    private Table2 table2;

   // Getters and Setters
}

@Entity
@Table(name="table2")
public class Table2 {
    private  Integer id;
    private  Integer column1_number;

    @Override
    public Integer getId() {
        return id;
    }

    @Override
    public void setId(Integer id) {
        this.id = id;
    }

   // Getters and Setters
}

存储库是:


@Repository
public interface Table1Repository extends JpaRepository<Table1, Integer> {

    @Query(value = "SELECT name FROM table1 t1 WHERE t1.table2_id IN (SELECT id FROM table2 t2 WHERE t2.column1_number = ?1 AND t2.id IS NOT NULL) ORDER BY t1.name", nativeQuery = true)
    List<Table1> findByNumberOrderByName(Integer number);
}

关于为什么我在 运行 时收到此错误的任何想法?编译时不会出现此错误。

您正在尝试使用 id 在 table2 中进行搜索,但是您没有从 table1 中选择正确的映射列,该列应该是 table2_id.id,因此查询应该像这样

SELECT name FROM table1 t1 WHERE t1.table2_id.id IN (SELECT id FROM table2 t2 WHERE t2.column1_number = 1 AND t2.id IS NOT NULL) ORDER BY t1.name 

另请注意您正在使用本机查询,这意味着直接查询数据库,因此请确保您在数据库表中使用相同的正确名称。

尝试将 Id 元素添加到 table1 并使用 @Id 注释对两个表的 Id 字段进行注释,如下所示。

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "id")
private Long id;
@Query(value = "SELECT name FROM table1 t1 WHERE t1.table2_id IN (SELECT id FROM table2 t2 WHERE t2.column1_number = ?1 AND t2.id IS NOT NULL) ORDER BY t1.name", nativeQuery = true)
    List<Table1> findByNumberOrderByName(Integer number);

应该是 List<String> 而不是 List<Table1>

所以解决方案是:

@Query(value = "SELECT name FROM table1 t1 WHERE t1.table2_id IN (SELECT id FROM table2 t2 WHERE t2.column1_number = ?1 AND t2.id IS NOT NULL) ORDER BY t1.name", nativeQuery = true)
    List<String> findByNumberOrderByName(Integer number);