如何从 IP 列表中找到最近的 IP?
How to find the closest IP from a list of IPs?
我想知道这是否可行
我有一个给定的 IP,例子:191.184.222.43 (public ipv4)
我还有一个其他 IP 地址的 Loong 列表,例如:
[ ip1, ip2, ip3, ip4 ...等等]
现在我必须找出列表中哪个 IP 最接近(物理上)我的 给定 IP (191.184.222.43 )
这可能吗?还是我的想法不一样
有很多API可以做到这一点的例子在https://ipstack.com/结束了。它基于 IP 进行地理定位,通过一些解析,您可以轻松完成此操作!
示例代码:
// set endpoint and your access key
var ip = '134.201.250.155'
var access_key = 'YOUR_ACCESS_KEY';
// get the API result via jQuery.ajax
$.ajax({
url: 'https://api.ipstack.com/' + ip + '?access_key=' + access_key,
dataType: 'jsonp',
success: function(json) {
// output the "capital" object inside "location"
alert(json.location.capital);
}
});
示例输出 (JSON):
[
{
"ip": "134.201.250.155",
"type": "ipv4",
"continent_code": "NA",
"continent_name": "North America",
"country_code": "US",
"country_name": "United States",
"region_code": "CA",
"region_name": "California",
"city": "Los Angeles",
"zip": "90013",
"latitude": 34.0453,
"longitude": -118.2413,
"location": { ... },
"time_zone": { ... },
"currency": { ... },
"connection": { ... },
}
]
我想知道这是否可行
我有一个给定的 IP,例子:191.184.222.43 (public ipv4)
我还有一个其他 IP 地址的 Loong 列表,例如:
[ ip1, ip2, ip3, ip4 ...等等]
现在我必须找出列表中哪个 IP 最接近(物理上)我的 给定 IP (191.184.222.43 )
这可能吗?还是我的想法不一样
有很多API可以做到这一点的例子在https://ipstack.com/结束了。它基于 IP 进行地理定位,通过一些解析,您可以轻松完成此操作!
示例代码:
// set endpoint and your access key
var ip = '134.201.250.155'
var access_key = 'YOUR_ACCESS_KEY';
// get the API result via jQuery.ajax
$.ajax({
url: 'https://api.ipstack.com/' + ip + '?access_key=' + access_key,
dataType: 'jsonp',
success: function(json) {
// output the "capital" object inside "location"
alert(json.location.capital);
}
});
示例输出 (JSON):
[
{
"ip": "134.201.250.155",
"type": "ipv4",
"continent_code": "NA",
"continent_name": "North America",
"country_code": "US",
"country_name": "United States",
"region_code": "CA",
"region_name": "California",
"city": "Los Angeles",
"zip": "90013",
"latitude": 34.0453,
"longitude": -118.2413,
"location": { ... },
"time_zone": { ... },
"currency": { ... },
"connection": { ... },
}
]