如何在 PhpSpreadsheet 中获取第一列索引

Question

我必须遍历 xls 文档前两列的所有行。问题是该特定文档的第一列是 "G"，索引为 7。

有没有办法获取第一列索引，因为我不想对其进行硬编码。

我的循环：

$spreadsheet =\PhpOffice\PhpSpreadsheet\IOFactory::load($path);
$worksheet = $spreadsheet->getActiveSheet();

$highestRow = $worksheet->getHighestRow();

$rows = [];
for ($row = 1; $row <= $highestRow; ++$row) {
    // I WANT TO REPLACE HARD-CODED VALUES OF 7 AND 8
    // WITH $firstCol and $firstCol+1
    for ($col = 7; $col <= 8; ++$col) { 
        $value = $worksheet->getCellByColumnAndRow($col, $row)->getValue();
        $rows[$row][$col] = $value;
    }
}

Answer 1

您可以添加一个 while 循环来跳过空单元格。试试这个：

$rows = [];
for ($row = 1; $row <= $highestRow; ++$row) {
    $col = 1;
    $cell = $worksheet->getCellByColumnAndRow($col, $row);
    // Skip empty cells
    while (in_array($cell->getValue(), [null, ''], true)) {
        $col++;
        $cell = $worksheet->getCellByColumnAndRow($col, $row);
    }
    $maxCol = $col + 1;
    for ( ; $col <= $maxCol; ++$col) { 
        $value = $worksheet->getCellByColumnAndRow($col, $row)->getValue();
        $rows[$row][$col] = $value;
    }
}

如何在 PhpSpreadsheet 中获取第一列索引

How to get first column index in PhpSpreadsheet

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