Bash 比较在 while 循环中不起作用的字符串

Question

我创建了这个 bash 脚本，但似乎无法弄清楚为什么我在 if 块中的代码没有执行。

db_instances_status="creating" 
db_instances_status=$(makes api request to get value)

COUNTER=0
while [ $COUNTER -lt 1 ]; do
  db_instances_status=$(makes api request to get value)

  echo "$db_instances_status" # echos available

  if [ "available" = "$db_instances_status" ]; then
     # code never makes it here
     dosomething()
     break;
  fi
  sleep 30
done

我遵循了这个 How to compare strings in Bash

中的示例

这里https://tecadmin.net/tutorial/bash/examples/check-if-two-strings-are-equal/

Answer 1

您要么没有得到 if 语句，要么变量不包含您认为的内容。

此代码段将有助于调试...

while [ $COUNTER -lt 1 ]; do
  echo "[DEBUG] getting status"
  db_instances_status=$(makes api request to get value)
  echo "[DEBUG] X${db_instances_status}X"
  echo "$db_instances_status" # echos available

  if [ "available" = "$db_instances_status" ]; then

Bash 比较在 while 循环中不起作用的字符串

Bash compare strings not working inside of while loop

bash

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