根据 SQL Server 2008 R2 中的最大值删除一行

Deleting a row based on the max value in SQL Server 2008 R2

我有@RankTable table,其中包含不同客户的借记。从这里我想删除每个排名最高的客户。

Declare @RankTable Table
(
   Customer_ID int,
   Debit decimal(18,2),
   Transaction_Date datetime,
   Sales_Master_ID int,
   Rank int,
   Rank1 int
)
Insert into @RankTable
  Select *,row_number()over(partition by (Customer_ID)  Order By 
    Customer_ID)as Rank1 
From @tempTable


Select  Customer_ID,Debit,Transaction_Date ,Sales_Master_ID,Rank1 from 
@RankTable Order By Customer_ID

我希望上述 table 的输出是: 我想删除排名最高的客户。 ex:I 想要删除 Customer_ID = 4 的行,其中 Rank1 = 20(对所有客户都是这样),但我无法删除

使用 CTE,以每个客户的最高排名记录为目标。

WITH cte AS (
    SELECT *,
        ROW_NUMBER() OVER (PARTITION BY Customer_ID ORDER BY Rank1 DESC) rn
    FROM @RankTable
)

DELETE
FROM cte
WHERE rn = 1;

这会起作用-

DELETE A
FROM @RankTable A
INNER JOIN
(
    SELECT ID,MAX(Rank1) Rank1
    FROM @RankTable 
    GROUP BY ID
) B
ON A.id = B.id and A.Rank1 = B.Rank1