抓取时是否可以选择绕过 python3 中的 Incapsula 保护？

Question

我是抓取的新手，我已经被 Incapsula 保护阻止了。

import bs4
from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup

my_url = 'https://www.immoweb.be/fr/recherche/immeuble-de-rapport/a-vendre'

# opening up connection, grabbing the page
uClient = uReq(my_url)
page_html = uClient.read()
uClient.close()

#html parsing
page_soup = soup(page_html, "html.parser")

page_soup.h1

我无法从网站访问任何数据，因为我被 InCapsula 问题阻止了...
当我输入时：

print(page_soup)

我收到这条消息：

<html style="height:100%"><head><meta content="NOINDEX, NOFOLLOW" name="ROBOTS"/><meta content="telephone=no" name="format-detection"/>
[...]
Request unsuccessful. Incapsula incident ID: 936002200207012991-

Answer 1

我做了这里描述的一些测试 and only the workaround of @Karl Anka成功了。

参见下面的示例：

from bs4 import BeautifulSoup
from selenium import webdriver

url = 'https://www.immoweb.be/fr/recherche/immeuble-de-rapport/a-vendre'

driver = webdriver.Chrome(executable_path='./chromedriver')
driver.get(url)

soup = BeautifulSoup(driver.page_source, features='html.parser')
driver.quit()

print(soup.prettify())

输出：

<html class="js flexbox rgba borderradius boxshadow opacity cssgradients csstransitions generatedcontent localstorage sessionstorage" style="" xmlns="http://www.w3.org/1999/xhtml" xmlns:fb="http://www.facebook.com/2008/fbml" xmlns:og="http://opengraphprotocol.org/schema/">
 <head>
  <script async="" src="https://c.pebblemedia.be/js/data/david/_david_publishers_master_produpress.js" type="text/javascript">
  </script>
  <script async="" src="https://scdn.cxense.com/cx.js" type="text/javascript">
  </script>
  <script async="" src="https://connect.facebook.net/signals/plugins/inferredEvents.js?v=2.8.47">
  </script>
  <script async="" src="https://connect.facebook.net/signals/config/1554445828209863?v=2.8.47&amp;r=stable">
  </script>
[...]

抓取时是否可以选择绕过 python3 中的 Incapsula 保护？

Any option to bypass Incapsula protection in python3 while scraping?

python

beautifulsoup

web-scraping

incapsula