sql 查询金额和汇率

Question

考虑到汇率如何选择2018年12月大额付款的客户

我有一个 table:

交易日期 - 交易日期
Transum numeric (20,2) - 支付金额
CurrencyRate numeric (20,2) - 货币汇率

 ID_Client  Trandate    Transum CurrencyRate    Currency
 --------------------------------------------------------
 1          2018.12.01  100     1               UAH
 1          2018.12.02  150     2               USD
 2          2018.12.01  200     1               UAH
 3          2018.12.01  250     3               EUR
 3          2018.12.02  300     1               UAH
 3          2018.12.03  350     2               USD
 7          2019.01.08  600     1               UAH

但我认为"max"根本不是我需要的

 SELECT ID_Client, MAX(Transum*CurrencyRate) 
 FROM `Payment.TotalPayments` 
 WHERE YEAR(Trandate) = 2018
       AND MONTH(Trandate) = 12

我需要这个

ID_Client   Transum 
   3         1750

其中1750是"UAH"和350USD + 300UAH + 250EUR，美元汇率为2，欧元汇率为3。

Answer 1

我想你想要 sum()。然后就可以order by结果：

SELECT ID_Client, SUM(Transum*CurrencyRate) as total 
FROM `Payment.TotalPayments` 
WHERE Trandate >= '2018-12-01' AND Transdate < '2019-01-01'
GROUP BY ID_Client
ORDER BY total DESC;

Answer 2

如果您要获取客户在 2018 年和 12 月份的交易金额总和，您可以这样写：

SELECT ID_Client, SUM(Transum*CurrencyRate) as payment_total_converted
FROM `Payment.TotalPayments` 
WHERE YEAR(Trandate) = 2018
and MONTH(Trandate) = 12
group by ID_Client

如果您希望在给定日期范围内按每个客户、年份和月份分组，您可以这样写：

SELECT ID_Client, YEAR(Trandate) as tran_year, MONTH(Trandate) as tran_month, 
SUM(Transum*CurrencyRate) as payment_total_converted
FROM `Payment.TotalPayments` 
WHERE Trandate between '2018-12-01' and '2019-01-01'
group by ID_Client, YEAR(Trandate), MONTH(Trandate)

我为您的计算列添加了一个列名，这样结果集仍然是相关的（列需要不同的名称）。

我建议您阅读 SQL 'group by' 子句 (https://www.w3schools.com/sql/sql_groupby.asp) and aggregate (https://www.w3schools.com/sql/sql_count_avg_sum.asp, https://www.w3schools.com/sql/sql_min_max.asp) 运算符。

sql 查询金额和汇率

sql quest with amount and exchange rate

sql

sql-server-2005