如何使用 Django orm 执行此查询?
How to do this query using Django orm?
我有一个 Profile 模型和 Complain 模型都连接到内置用户 model.I 必须使用 Profile 模型所在的两者进行查询。我想统计一个特定住所提出的投诉数量。我可以使用 SQL 来完成,但我不知道如何使用 Django 来完成。
SELECT users_profile.residence,count(user_id)from users_profile INNER JOIN chp_complain on(users_profile.user_id = chp_complain.complain_user_id)GROUP BY(user_id)
投诉模特:-
class Complain(models.Model):
complain_user = models.ForeignKey(User, on_delete=models.CASCADE)
complain_department=models.CharField(max_length=100)
complain_subject = models.CharField(max_length = 100,help_text = "Enter the complain subject")
department_head=models.CharField(max_length=100)
recepient=models.CharField(max_length=100)
complain_description=models.TextField(max_length=2000)
date_posted = models.DateTimeField(default = timezone.now)
NOT_VISITED = 'NV'
VISITED = 'V'
INPROCESS = 'IP'
COMPLETED = 'C'
status = (
(NOT_VISITED, 'NV'),
(VISITED, 'V'),
(INPROCESS, 'IP'),
(COMPLETED, 'C'),)
status=models.CharField(max_length=2,choices=status,)
个人资料模型:-
class Profile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
UID =models.CharField(max_length=30,default = "000",help_text = "'Staff's fill their STAFF ID and student's fill their ROLL NO " )
MALE = 'M'
FEMALE = 'F'
Gender=((MALE, 'Male'),(FEMALE, 'Female'),)
Gender=models.CharField(max_length=6,choices=Gender,default=MALE,)
FIRST = '1st'
SECOND = '2nd'
THIRD = '3rd'
FOURTH = '4th'
NGH = 'NGH'
NON_HOSTELER = 'Non_hosteler'
TEACHER_QUARTER = 'Teacher_quarter'
residence = ((FIRST, 'First'),(SECOND, 'Second'),(THIRD, 'Third'),(FOURTH, 'Fourth'),(NGH,'NGH'),(NON_HOSTELER, 'Non_hosteler'),(TEACHER_QUARTER,'Teacher_quarter'))
residence = models.CharField(max_length=20,choices=residence,default=FIRST,)
room_no=models.CharField(max_length=10,default = "000")
我想统计一下,您可以写下来自特定住所的投诉数量:
Complain.objects.values('complain_user__profile__residence').annotate(complains_count=Count('id'))
在您的 SQL 查询中:
SELECT users_profile.residence,count(user_id)from users_profile INNER JOIN chp_complain on(users_profile.user_id = chp_complain.complain_user_id)GROUP BY(user_id)
您计算有多少用户从特定住所提出投诉。可以这样计算:
User.objects.values('profile__residence').annotate(Count('id'))
我有一个 Profile 模型和 Complain 模型都连接到内置用户 model.I 必须使用 Profile 模型所在的两者进行查询。我想统计一个特定住所提出的投诉数量。我可以使用 SQL 来完成,但我不知道如何使用 Django 来完成。
SELECT users_profile.residence,count(user_id)from users_profile INNER JOIN chp_complain on(users_profile.user_id = chp_complain.complain_user_id)GROUP BY(user_id)
投诉模特:-
class Complain(models.Model):
complain_user = models.ForeignKey(User, on_delete=models.CASCADE)
complain_department=models.CharField(max_length=100)
complain_subject = models.CharField(max_length = 100,help_text = "Enter the complain subject")
department_head=models.CharField(max_length=100)
recepient=models.CharField(max_length=100)
complain_description=models.TextField(max_length=2000)
date_posted = models.DateTimeField(default = timezone.now)
NOT_VISITED = 'NV'
VISITED = 'V'
INPROCESS = 'IP'
COMPLETED = 'C'
status = (
(NOT_VISITED, 'NV'),
(VISITED, 'V'),
(INPROCESS, 'IP'),
(COMPLETED, 'C'),)
status=models.CharField(max_length=2,choices=status,)
个人资料模型:-
class Profile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
UID =models.CharField(max_length=30,default = "000",help_text = "'Staff's fill their STAFF ID and student's fill their ROLL NO " )
MALE = 'M'
FEMALE = 'F'
Gender=((MALE, 'Male'),(FEMALE, 'Female'),)
Gender=models.CharField(max_length=6,choices=Gender,default=MALE,)
FIRST = '1st'
SECOND = '2nd'
THIRD = '3rd'
FOURTH = '4th'
NGH = 'NGH'
NON_HOSTELER = 'Non_hosteler'
TEACHER_QUARTER = 'Teacher_quarter'
residence = ((FIRST, 'First'),(SECOND, 'Second'),(THIRD, 'Third'),(FOURTH, 'Fourth'),(NGH,'NGH'),(NON_HOSTELER, 'Non_hosteler'),(TEACHER_QUARTER,'Teacher_quarter'))
residence = models.CharField(max_length=20,choices=residence,default=FIRST,)
room_no=models.CharField(max_length=10,default = "000")
我想统计一下,您可以写下来自特定住所的投诉数量:
Complain.objects.values('complain_user__profile__residence').annotate(complains_count=Count('id'))
在您的 SQL 查询中:
SELECT users_profile.residence,count(user_id)from users_profile INNER JOIN chp_complain on(users_profile.user_id = chp_complain.complain_user_id)GROUP BY(user_id)
您计算有多少用户从特定住所提出投诉。可以这样计算:
User.objects.values('profile__residence').annotate(Count('id'))