将数组切片到 seq 没有副本

Question

我正在尝试获取 Array 的一部分作为 Seq 避免复制。我可以使用 toSeq 方法。

val array = Array[AnyRef](
  new Integer(1), 
  new Integer(2), 
  new Integer(3), 
  new Integer(4), 
  new Integer(5)
)
val seq = array.toSeq
array(1) = null
println(seq.mkString(",")) //1,null,3,4,5

工作正常：Ideone Live example。数组未被复制。但是当我尝试切片时

val array = Array[AnyRef](
  new Integer(1),
  new Integer(2),
  new Integer(3),
  new Integer(4),
  new Integer(5)
)
val seq = array.toSeq.slice(0, 3)
array(1) = null
println(seq.mkString(",")) //1,2,3

可以看出复制已完成：Ideone Live Example。我试图避免它。有没有办法在 Scala 中做到这一点？

Answer 1

代码如下：

val a = (0 to 10).toArray
val b = a.toSeq.view.slice(1, 9)
a(5) = 12345
b.mkString(",") // res5: String = 1,2,3,4,12345,6,7,8

这里是 quote from Jurassic Park：

"Your scientists were so preoccupied with whether or not they could that they didn't stop to think if they should."

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