Swift

Question

我尝试设置一个按钮来朗读标签中的文本（使用不同的声音/语言），但是当有运算符符号（+、-、×）时，语音效果不佳，任何想法解决这个问题？

我试过了：

//Option 1
TextLabel.text = "1 + 2 - 3 × 4" // Result: "+" = "and" other voice "plus" (ok), "-" = mute, "×" = mute, other voice "X" (letter)

//Option 2
TextLabel.text = "1 ➕ 2 ➖ 3 ✖️ 4" // Result: "+" = plus symbol, "-" = minus symbol, "×" = multiplication symbol

import UIKit
import AVFoundation
import Speech

class ViewController: UIViewController {
    let synth = AVSpeechSynthesizer()

    @IBAction func speaker(_ sender: UIButton) {
        if (!synth.isSpeaking) {
            let speech = AVSpeechUtterance(string: TextLabel.text!)

            speech.voice = AVSpeechSynthesisVoice(language: "en-US")
            speech.rate = 0.5
            speech.pitchMultiplier = 1
            speech.volume = 1
            synth.speak(speech)
        }
    }

    @IBOutlet weak var TextLabel: UILabel!

    //Option 1
    TextLabel.text = "1 + 2 - 3 × 4" // "+" = "and" other voice "plus" (ok), "-" = mute, "×" = mute, other voice "X" (letter)

    //Option 2
    TextLabel.text = "1 ➕ 2 ➖ 3 ✖️ 4" // "+" = plus symbol, "-" = minus symbol, "×" = multiplication symbol
}

我希望使用 AVSpeechSynthesisVoice 在不同语言中正确地表达符号 +（加号）、-（减号）、×（次），但选项 1 不正确或使某些符号静音...而选项 2 是更好，但重现单词 "symbol"

Answer 1

...the speech is not working very well when there are operator symbols (+, -, ×), any idea to fix this problem?

要获得最准确的结果，您应该删除任何不明确的符号 （无法可靠地检测必须读出的上下文） 并将它们替换为 spelled-out 形式。

I expect speech the symbol + (plus), - (minus), ×(times) correctly in different languages...

我建议使用NSLocalizedString(, comment:)，以便您的每个符号都能以不同的语言读出。

下面提供了一个非常简单的例子(删除并替换符号):

class ViewController: UIViewController {

    var synthesizer = AVSpeechSynthesizer()

    override func viewDidAppear(_ animated: Bool) {
        super.viewDidAppear(animated)

        let string1 = "1"
        let string2 = "5"
        let result = "6"

        let finalString = string1 + NSLocalizedString("MyPlus", comment: "") + string2 + NSLocalizedString("MyEqual", comment: "") + result

        let utterance = AVSpeechUtterance(string: finalString)
        let synthesizer = AVSpeechSynthesizer()
        synthesizer.speak(utterance)
    }
}

为每种语言创建一个 Localizable.strings，例如，您在其中用英语定义以下术语：

"MyPlus" = " plus ";
"MyEqual" = " is equal to ";

Answer 2

你可以使用符号，只是用自定义发音来代替说话。

import AVFoundation

let text = "1 ➕ 2 ➖ 3 ✖️ 4"
let rangeOne = NSString(string: text).range(of: "➕")
let rangeTwo = NSString(string: text).range(of: "➖")
let rangeThree = NSString(string: text).range(of: "✖️")
let mutableAttributedString = NSMutableAttributedString(string: text)

let pronunciationKey = NSAttributedString.Key(rawValue: AVSpeechSynthesisIPANotationAttribute)
mutableAttributedString.setAttributes([pronunciationKey: "plʌs"], range: rangeOne)

mutableAttributedString.setAttributes([pronunciationKey: "ˈmaɪ.nəs"], range: rangeTwo)

mutableAttributedString.setAttributes([pronunciationKey: "taɪmz"], range: rangeThree)
let utterance = AVSpeechUtterance(attributedString: mutableAttributedString)


utterance.voice = AVSpeechSynthesisVoice(language: "en-GB")

let synthesizer = AVSpeechSynthesizer()
synthesizer.speak(utterance)

来自 NShipster

AVUtterance added functionality to control the pronunciation of particular words, which is especially helpful for proper names.

To take advantage of it, construct an utterance using init(attributedString:) instead of init(string:). The initializer scans through the attributed string for any values associated with the AVSpeechSynthesisIPANotationAttribute, and adjusts pronunciation accordingly.

Swift - 基本运算符 - 符号（+、-、×）怎么读？

Swift - How Speech basic operator - Symbol (+, -, ×)?

speech-recognition

avspeechsynthesizer