组合值和键以形成 json 对象
Combine values and keys to form json object
我有键和值作为字符串,我需要将它们组合成 json 格式。
例如:我的 "keys"
字符串数组是:{"a","b","c","d"}
我的 "values"
字符串数组我正在通过一个 for 循环,因为它存储在数组 X
中
X[0], X[1], X[2] and so on..
如何将 "keys"
和 "values"
组合成这样:
{ "a":"x","b":"y", "c":"z", "d":"q"
}
我试过迭代和合并,但我卡住了
std::string values="";
std::string keys[4]={"a","b","c","d"};
..
..
..
for(int i=0;i<4;i++)
{
values= values + "," + x[i];
}
我对如何组合这两个字符串并显示如下所示的结果字符串感到困惑:
{ "a":"x",
"b":"y",
"c":"z",
"d":"q"
}
手动方式可以像这样完成:
std::string res = "{";
std::string keys[4]={"a","b","c","d"};
std::string values[4]={"a","b","c","d"};
const char* sep = "";
for(int i=0;i<4;i++)
{
res += sep + keys[i] + ":" + values[i];
sep = ",";
}
res += "}";
使用任何 json 库,您可以执行如下操作:
Json::Value root(Json::ValueType::objectValue);
for (int i = 0; i < 4; i++) {
root[keys[i]] = values[i];
}
Json::StyledWriter writer;
writer.write(root);
我有键和值作为字符串,我需要将它们组合成 json 格式。
例如:我的 "keys"
字符串数组是:{"a","b","c","d"}
我的 "values"
字符串数组我正在通过一个 for 循环,因为它存储在数组 X
X[0], X[1], X[2] and so on..
如何将 "keys"
和 "values"
组合成这样:
{ "a":"x","b":"y", "c":"z", "d":"q"
}
我试过迭代和合并,但我卡住了
std::string values="";
std::string keys[4]={"a","b","c","d"};
..
..
..
for(int i=0;i<4;i++)
{
values= values + "," + x[i];
}
我对如何组合这两个字符串并显示如下所示的结果字符串感到困惑:
{ "a":"x",
"b":"y",
"c":"z",
"d":"q"
}
手动方式可以像这样完成:
std::string res = "{";
std::string keys[4]={"a","b","c","d"};
std::string values[4]={"a","b","c","d"};
const char* sep = "";
for(int i=0;i<4;i++)
{
res += sep + keys[i] + ":" + values[i];
sep = ",";
}
res += "}";
使用任何 json 库,您可以执行如下操作:
Json::Value root(Json::ValueType::objectValue);
for (int i = 0; i < 4; i++) {
root[keys[i]] = values[i];
}
Json::StyledWriter writer;
writer.write(root);