如果条件为真显示阻止按钮否则条件为假显示取消阻止按钮：Laravel、Javascript

Question

If $block->user_username 数据为空显示 block 按钮 else 运行另一个 if 和 else 条件。但是在 foreach 循环中其他不起作用 @else <a href="#0" class="cd-popup-trigger">Block2</a> 请任何人帮助我。任何人都知道做这件事的任何其他条件。

@else <a href="#0" class="cd-popup-trigger">Block2</a> @endif 这个 else 条件只有在条件有效时才会卡住。如果此 @if(Auth::user()->name == $block->user_username && $user->username == $block->block_username) 条件为假，则代码未显示其他条件。

 @foreach($blocked as $block)    
                   @if(empty($block->user_username ))
                     <a href="#0" class="cd-popup-trigger">Block1</a>

                   @else
                        @if(Auth::user()->username == $block->user_username and $user->username == $block->block_username)
                         <a href="#0" class="cd-popup-trigger">Unblock</a>
                         @else
                            <a href="#0" class="cd-popup-trigger">Block2</a>
                        @endif
                    @endif
            @endforeach

Answer 1

试试这个代码

@foreach($blocked as $block)    
  @if(!empty($block->user_username ))
    @if(Auth::user()->name == $block->user_username && $user->username == $block->block_username)
      <a href="#0" class="cd-popup-trigger">Unblock</a>
    @else
      <a href="#0" class="cd-popup-trigger">Block2</a>
    @endif
  @else
     <a href="#0" class="cd-popup-trigger">Block1</a> 
  @endif
@endforeach

希望对你有所帮助

如果条件为真显示阻止按钮否则条件为假显示取消阻止按钮：Laravel、Javascript

if condition is true show block button else condition false show unblock button : Laravel, Javascript

javascript

php

laravel

eloquent

laravel-5.8