如何在没有多次上传的情况下存储数据"if i don't have a file want to upload"?

How to store data without multiple uploads "if i don't have a file want to upload"?

我想保存新数据时遇到问题我也不想上传文件,但我必须在我的 public 函数存储中编写多个上传代码。我想在打开编辑表单并上传时添加文件。我该怎么办?

我尝试设置验证设置但是当我提交错误未定义的变量:数据。

public function store(Request $request)
{
    $request->validate([
        'employee_sid' => 'required',
        'employee_npk' => 'required',
        'employee_name' => 'required',
        'file_uploads' => 'nullable',
        'file_uploads.*' => 'file|image|mimes:pdf,jpg,jpeg,png',
    ]);

    if($request->file('file_uploads'))
    {
        foreach($request->file('file_uploads') as $file)
        {
            $name = $file->getClientOriginalName();
            $path = 'public/file/'.$request->employee_name;
            $file->move($path, $name);
            $data[] = $name;
        }
    }

    $sid = new Sid;
        $sid->employee_sid          = $request->employee_sid;
        $sid->employee_npk          = $request->employee_npk;
        $sid->employee_name         = $request->employee_name;
        $sid->file_uploads          = json_encode($data);
        $sid->save();

我希望当我提交没有 file_uploads 的数据时它会。但错误

Undefined variable: data.

您是在 if 中定义 $data 变量,因此如果条件为假,则不会定义 $data 变量。一种可能的解决方法是:

$sid = new Sid;
    $sid->employee_sid = $request->employee_sid;
    $sid->employee_npk = $request->employee_npk;
    $sid->employee_name = $request->employee_name;
    $sid->file_uploads = isset($data)? json_encode($data): null;
    $sid->save();