可选参数约束
Optional argument constraint
框架:机器人,语言: Python-3.7.1 熟练程度:新手
我有以下核心方法,它在匹配时替换动态位置,并在我现有的自动化脚本中广泛使用。
def querybuilder(self, str, symbol, *args):
count = str.count(symbol)
str = list(str)
i = 0
j = 0
if (count == (len(args))):
while (i < len(str)):
if (str[i] == symbol):
str[i] = args[j]
j = j + 1
i = i + 1
else:
return ("Number of passed arguments are either more or lesser than required.")
return ''.join(str)
如果像下面这样发送参数,这就可以正常工作
def querybuilder("~test~123", "~", "foo","boo")
但是如果我想作为一个列表来代替可选参数发送,它将每个 list/tuple/array 作为一个参数,因此不会进入 if 条件。
例如:-
i = ["foo", "boo"] -- Optional argument consider it as ('foo, boo',)
显然,由于现有框架中广泛使用的 -ve 影响,我无法对方法 (querybuilder) 进行任何更改。
我试图摆脱的东西:-
1, ", ".join("{}".format(a) for a in i,
2, tuple(i),
3, list(i),
4, numpy.array(i) part of import numpy
任何可能的解决方案来根据要求转换参数?
将您的列表作为 *['foo', 'boo']
传递
def querybuilder(s, symbol, *args):
count = s.count(symbol)
st = list(s)
i = 0
j = 0
if (count == (len(args))):
while (i < len(st)):
if (st[i] == symbol):
st[i] = args[j]
j = j + 1
i = i + 1
else:
return ("Number of passed arguments are either more or lesser than required.")
return ''.join(st)
print(querybuilder("~test~123", "~", "foo","boo"))
# footestboo123
print(querybuilder("~test~123", "~", *["foo","boo"]))
# footestboo123
框架:机器人,语言: Python-3.7.1 熟练程度:新手
我有以下核心方法,它在匹配时替换动态位置,并在我现有的自动化脚本中广泛使用。
def querybuilder(self, str, symbol, *args):
count = str.count(symbol)
str = list(str)
i = 0
j = 0
if (count == (len(args))):
while (i < len(str)):
if (str[i] == symbol):
str[i] = args[j]
j = j + 1
i = i + 1
else:
return ("Number of passed arguments are either more or lesser than required.")
return ''.join(str)
如果像下面这样发送参数,这就可以正常工作
def querybuilder("~test~123", "~", "foo","boo")
但是如果我想作为一个列表来代替可选参数发送,它将每个 list/tuple/array 作为一个参数,因此不会进入 if 条件。
例如:-
i = ["foo", "boo"] -- Optional argument consider it as ('foo, boo',)
显然,由于现有框架中广泛使用的 -ve 影响,我无法对方法 (querybuilder) 进行任何更改。
我试图摆脱的东西:-
1, ", ".join("{}".format(a) for a in i,
2, tuple(i),
3, list(i),
4, numpy.array(i) part of import numpy
任何可能的解决方案来根据要求转换参数?
将您的列表作为 *['foo', 'boo']
def querybuilder(s, symbol, *args):
count = s.count(symbol)
st = list(s)
i = 0
j = 0
if (count == (len(args))):
while (i < len(st)):
if (st[i] == symbol):
st[i] = args[j]
j = j + 1
i = i + 1
else:
return ("Number of passed arguments are either more or lesser than required.")
return ''.join(st)
print(querybuilder("~test~123", "~", "foo","boo"))
# footestboo123
print(querybuilder("~test~123", "~", *["foo","boo"]))
# footestboo123