如何按创建日期和文件大小比较不同的文件？

Question

我想查看最近 2 天的备份文件并比较是否当前文件的大小（今天）大于另一个（昨天）不同的备份文件名。

我有 10 台服务器 MYSQL 并且每天从数据库创建每个服务器的备份并发送到备份服务器。

某些服务器有多个数据库，因此服务器在同一天创建不同的备份文件并发送到备份服务器。一世需要确定今天是否进行了备份以及文件（今天）是否比旧文件大（昨天）？

55M 25. Mai 03:45 /home/backup/server1/SW1_20190525.sql.gz

48M 25. Mai 03:45 /home/backup/server1/SW2_20190525.sql.gz

39M 25. Mai 03:45 /home/backup/server1/SW3_20190525.sql.gz

35M 25. Mai 03:45 /home/backup/server1/SW4_20190525.sql.gz

42M 25. Mai 03:45 /home/backup/server1/SW5_20190525.sql.gz

57M 26. Mai 03:45 /home/backup/server1/SW1_20190526.sql.gz

51M 26. Mai 03:45 /home/backup/server1/SW2_20190526.sql.gz

20K 26. Mai 03:45 /home/backup/server1/SW3_20190526.sql.gz

45M 26. Mai 03:45 /home/backup/server1/SW4_20190526.sql.gz

48M 26. Mai 03:45 /home/backup/server1/SW5_20190526.sql.gz

i expect to check:

SW1_20190526.sql.gz > SW1_20190525.sql.gz

SW2_20190526.sql.gz > SW2_20190525.sql.gz

SW3_20190526.sql.gz > SW3_20190525.sql.gz

SW4_20190526.sql.gz > SW4_20190525.sql.gz

SW5_20190526.sql.gz > SW5_20190525.sql.gz

when OK say 0 OK

when not say 1 Error (for example => SW3_20190526.sql.gz)

Answer 1

只需将 ~/testing/* 更改为 path/to/your/files* 记得把 *

注意：此版本的脚本假定您运行它在所需的日期。例如（date-command 和最新的文件条目匹配）

# Set directory to loop through
dir=~/testing/*

# Todays date used to grep for today's file
today=$(date +%Y%m%d)

# Yesterday's date used to grep for yesterday's file
yesterday=$(date -d "yesterday" '+%Y%m%d')

# Start point to loop through each SW? files
num=1

# Start looping through directory
for file in $dir; do

    # Get today's file by date
    file_td=$(ls SW[$num]* | grep $today)

    # Get yesterday's file by date 
    file_yd=$(ls SW[$num]* | grep $yesterday)

    # Get size of today's file
    size_td=$(stat -c %s $file_td)

    # Get size of yesterday's file
    size_yd=$(stat -c %s $file_yd)

    # Test if file size is equal or greater than
    if (($size_td >= $size_yd)); then
        echo "$file_td is equal or bigger that $file_yd"
    else
        echo "$file_yd is bigger $file_td"
    fi

    # Limit SW? to 5 so its doesn't attempt the script on none existing file
    # You change the 5 to how ever many SW's there are in the directory
    ((num++)) && [[ $num > 5 ]] && exit

done

注意：这个版本的脚本不做任何假设，只是抓取目录接受的最后两个条目。这模拟了 "today" 和 "yesterday" 而不需要你在最后一天运行脚本。

# File Directory to loop through
dir=~/testing/*

# Starting point for file names SW1 - SW?
num=1

# Begin looping through directory
for file in $dir; do

    # Set the latest file in directory SW? to today
    file_td=$(ls SW[$num]* | sort -u -r | sed '1q;d')        

    # Set the second latest file in directory SW? to yesterday
    file_yd=$(ls SW[$num]* | sort -u -r | sed '2q;d')

    # Get size of today's file
    size_td=$(stat -c %s $file_td)

    # Get size of yesterday's file
    size_yd=$(stat -c %s $file_yd)

     # Test if file size is equal or greater than
    if (($size_td >= $size_yd)); then
        echo "$file_td is equal or bigger that $file_yd"
    else
        echo "$file_yd is bigger $file_td"
    fi

    # Limit SW? to 5 so its doesn't attempt the script on none existing files
    # You change the 5 to how ever many SW's there are in the directory 
    ((num++)) && [[ $num > 5 ]] && exit

done

如何按创建日期和文件大小比较不同的文件？

How can I compare different files by creation date and file size?

bash

database-backups