如何 multiply/divide 一个功能到另一个?如何使用参数?
How to multiply/divide one function to another ? How to use parameters?
如何将一个函数乘以另一个函数?以及如何正确使用参数?
我不太确定,我真的是 C++ 的新手,只有大约 14 周的 class 时间。
我尝试过创建一个新函数来乘以其他函数,并在参数中放入函数名称。
例如:
float mealMath(numberOfAdults, mealChoosing){
//Rest of function
}
但我总是得到 error.Please 解释如何解决这个问题,这对我来说是编程的一大障碍,我似乎无法掌握如何解决这个问题或着手做这些事情。别为了this.Thanks对我太苛刻了!
int numberOfAdults(){
int totalAdults;
cout << "Now how many adults will there be?: ";
cin >> totalAdults;
cout << "It seems there will be: " << totalAdults << " Adults." << endl;
while(totalAdults < 1){
cout << "Sorry there has to be a minimum of 1 adult!" << endl;
cout << "How many adults: ";
cin >> totalAdults;
}
return 0;
}
int numberOfKids(){
int totalKids;
cout << "Now how many Kids will there be?: ";
cin >> totalKids;
cout << "It seems there will be: " << totalKids << " kids." << endl;
while(totalKids < 0){
cout << "Sorry there has to be a minimum of 1 Kid!" << endl;
cout << "How many Kids: ";
cin >> totalKids;
}
return 0;
}
float mealChoosing(){
float cost;
string mealChoise;
cout << " " << endl;
cout << "Now, What meal will you be getting(D/S): ";
cin >> mealChoise;
if(mealChoise == "D"){
cout << "It seems you have selected the Deluxe Meal plan for everyone!" << endl;
cost = 25.95;
}
if(mealChoise == "S"){
cout << "It seems you have selected the Standard Meal plan for everyone!" << endl;
cost = 21.75;
}
cout << " " << endl;
return cost;
}
一个预期的结果是我想将用户在函数 "numberOfAdults" 中提供的输入乘以用户在 "mealChoosing"
中提供的输入
所以我想要 numberOfAdults * mealChoosing 但我想在不同的函数中完成所以
"float total(){
float totalBill;
totalBill = numberOfAdults * mealChoosing;
cout << totalBill;"
或类似的东西。我无法完成这个项目,因为出于某种原因我无法正确地为函数提供参数中所需的正确信息。
在这种情况下(以及大多数情况下),您不应声明其参数为函数的函数。而是使用整数和浮点输入声明 mealMath:
float mealMath(int a, float b){/*Your code here*/}
然后调用 mealMath 并将其他两个函数作为参数传递。
float x = mealMath(numberOfAdults(), mealChoosing());
或者,您可以没有 mealMath()
的函数参数,而是从函数内部调用 numberOfAdults()
和 mealChoosing()
。
重要的是要注意,大多数时候您将调用一个函数并将其输出用作参数,因此您需要将 ()
放在函数标识符之后,而不是只需单独输入标识符。
喜欢 mealChoosing()
return totalAdults
和 totalKids
(虽然这里不需要)分别来自 numberOfAdults()
、numberOfKids()
。
int numberOfAdults() {
//...
return totalAdults;
}
int numberOfKids() {
//..
return totalKids;
}
float mealChoosing() {
//..
return cost;
}
现在 mealMath(numberOfAdults, mealChoosing)
float mealMathOutput = mealMath(numberOfAdults(), mealChoosing());
如何将一个函数乘以另一个函数?以及如何正确使用参数?
我不太确定,我真的是 C++ 的新手,只有大约 14 周的 class 时间。
我尝试过创建一个新函数来乘以其他函数,并在参数中放入函数名称。
例如:
float mealMath(numberOfAdults, mealChoosing){
//Rest of function
}
但我总是得到 error.Please 解释如何解决这个问题,这对我来说是编程的一大障碍,我似乎无法掌握如何解决这个问题或着手做这些事情。别为了this.Thanks对我太苛刻了!
int numberOfAdults(){
int totalAdults;
cout << "Now how many adults will there be?: ";
cin >> totalAdults;
cout << "It seems there will be: " << totalAdults << " Adults." << endl;
while(totalAdults < 1){
cout << "Sorry there has to be a minimum of 1 adult!" << endl;
cout << "How many adults: ";
cin >> totalAdults;
}
return 0;
}
int numberOfKids(){
int totalKids;
cout << "Now how many Kids will there be?: ";
cin >> totalKids;
cout << "It seems there will be: " << totalKids << " kids." << endl;
while(totalKids < 0){
cout << "Sorry there has to be a minimum of 1 Kid!" << endl;
cout << "How many Kids: ";
cin >> totalKids;
}
return 0;
}
float mealChoosing(){
float cost;
string mealChoise;
cout << " " << endl;
cout << "Now, What meal will you be getting(D/S): ";
cin >> mealChoise;
if(mealChoise == "D"){
cout << "It seems you have selected the Deluxe Meal plan for everyone!" << endl;
cost = 25.95;
}
if(mealChoise == "S"){
cout << "It seems you have selected the Standard Meal plan for everyone!" << endl;
cost = 21.75;
}
cout << " " << endl;
return cost;
}
一个预期的结果是我想将用户在函数 "numberOfAdults" 中提供的输入乘以用户在 "mealChoosing"
中提供的输入所以我想要 numberOfAdults * mealChoosing 但我想在不同的函数中完成所以
"float total(){
float totalBill;
totalBill = numberOfAdults * mealChoosing;
cout << totalBill;"
或类似的东西。我无法完成这个项目,因为出于某种原因我无法正确地为函数提供参数中所需的正确信息。
在这种情况下(以及大多数情况下),您不应声明其参数为函数的函数。而是使用整数和浮点输入声明 mealMath:
float mealMath(int a, float b){/*Your code here*/}
然后调用 mealMath 并将其他两个函数作为参数传递。
float x = mealMath(numberOfAdults(), mealChoosing());
或者,您可以没有 mealMath()
的函数参数,而是从函数内部调用 numberOfAdults()
和 mealChoosing()
。
重要的是要注意,大多数时候您将调用一个函数并将其输出用作参数,因此您需要将 ()
放在函数标识符之后,而不是只需单独输入标识符。
喜欢 mealChoosing()
return totalAdults
和 totalKids
(虽然这里不需要)分别来自 numberOfAdults()
、numberOfKids()
。
int numberOfAdults() {
//...
return totalAdults;
}
int numberOfKids() {
//..
return totalKids;
}
float mealChoosing() {
//..
return cost;
}
现在 mealMath(numberOfAdults, mealChoosing)
float mealMathOutput = mealMath(numberOfAdults(), mealChoosing());