如何使用 jquery 中的父函数获取 class 名称

Question

如何在单击函数 addIncludeTextBox 时获得 'field_wrapper_1' class 名称？

<div class="field_wrapper_1">
        <span class="error php-error" id="php-error_includes" style="display: none"></span> 
    <div class="row">
        <div class="col-md-11">
            <div class="form_group">
                <label class="form_label">Includes <span>*</span></label>
                <input class="form_input" name="includes[][]" id="includes" placeholder="Enter the details of fees includes" type="text">                                    

            </div>
        </div>
        <div style="padding-top: 3.6%;" class="col-md-1">
            <a href="javascript:void(0);" class="add_button" onclick="addIncludeTextBox(this)" title="Add field"><i class="fa fa-plus" aria-hidden="true"></i></a>
        </div>
    </div>
</div>

Answer 1

你可以这样做：

$(obj).closest('[class^=field_wrapper]').attr("class")

合并 .closest 和 .attr 得到 class。

可选你也可以只使用.closest('.field_wrapper_1')

工作演示

function addIncludeTextBox(obj){
  console.log($(obj).closest('[class^=field_wrapper]').attr("class"))
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="field_wrapper_1">
        <span class="error php-error" id="php-error_includes" style="display: none"></span> 
    <div class="row">
        <div class="col-md-11">
            <div class="form_group">
                <label class="form_label">Includes <span>*</span></label>
                <input class="form_input" name="includes[][]" id="includes" placeholder="Enter the details of fees includes" type="text">                                    

            </div>
        </div>
        <div style="padding-top: 3.6%;" class="col-md-1">
            <a href="javascript:void(0);" class="add_button" onclick="addIncludeTextBox(this)" title="Add field"><i class="fa fa-plus" aria-hidden="true">+</i></a>
        </div>
    </div>
</div>

如何使用 jquery 中的父函数获取 class 名称

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