Perl:在考虑夏令时的纪元以来以秒为单位输入时间时获取 gmtime 和本地时间之间的偏移量

Perl : Get offset between gmtime and localtime when input time in seconds since epoch which considers daylight savings time

我想获得自纪元以来给定微秒数的本地时间和 gmtime 之间的小时偏移量。到目前为止我所拥有的是这样的

# Microseconds since Epoch 
my $msec = 555329743301750;

# Convert to seconds 
my $sec = $msec/1000000;

my $val = (POSIX::mktime(localtime $sec) - POSIX::mktime(gmtime $sec)) / 60 / 60;

print "$val\n";

1) 我得到的输出是 -6。(CST 本地时间)但是我期待 -5。我期望的行为类似于 运行 bash 命令

的结果
`date -d 20190514 "+%z"`; 

2) 长话短说,我如何计算类似于 perl 中的 date -d 20190514 "+%z" 的偏移量?

使用核心Time::Piece:

use strict;
use warnings;
use Time::Piece;

# Microseconds since Epoch 
my $usec = 555329743301750;

# Convert to seconds 
my $sec = $usec/1000000;

my $offset = localtime($sec)->tzoffset / 3600;

Time::Moment 和 DateTime 也可以 return 这个值,如果你像我在 上展示的那样构造它们的话。

my $offset = $time_moment->offset / 60;

my $offset = $datetime->offset / 3600;

您也可以根据日期创建这些对象,但它当然会为您提供当天午夜(当地时间)的偏移量。

use Time::Piece;
my $time = localtime->strptime('20190514', '%Y%m%d');

use Time::Moment;
use Role::Tiny ();
my $class = Role::Tiny->create_class_with_roles('Time::Moment', 'Time::Moment::Role::TimeZone');
my $time = $class->new(year => 2019, month => 5, day => 14)->with_system_offset_same_local;

use DateTime;
my $time = DateTime->new(year => 2019, month => 5, day => 14, time_zone => 'local');

这将为您提供与 Linux "%z" 格式相同的 [+-]HHMM 格式:

use POSIX qw[mktime];

my $tz = (localtime time)[8] * 60 - mktime(gmtime 0) / 60;
$tz = sprintf "%+03d%02d\n", $tz / 60, abs($tz) % 60;

如果您只想要以小时为单位的偏移量,您可以这样做:

my $tz_offset_hours = (localtime time)[8] - mktime(gmtime 0)) / 3600;

奖励: 以下子例程将 return 带有时区偏移量和微秒的完整时间戳,如“YYYY-MM-DD HH:MM:SS。 nnnnnn [+-]HHMM":

use POSIX qw[mktime strftime];
use Time::HiRes qw[gettimeofday];

sub timestamp () {
  my @now = gettimeofday;
  my $tz  = (localtime $now[0])[8] * 60 - mktime(gmtime 0) / 60;
  my $ts  = strftime("%Y-%m-%d %H:%M:%S", localtime $now[0]);
  return sprintf "%s.%06d %+03d%02d", $ts, $now[1], $tz / 60, abs($tz) % 60;
}