如何读取数字组合文件并将每个组合保存为新文件名？

Question

我有一个包含特定组合数字的组合文件，例如：

(133, 134), (133, 100), (133, 438), (133, 414), (133, 35), (133, 130), (133, 143), (133, 383), (134, 100), (134, 438), (134, 414), (134, 35), (134, 130), (134, 143), (134, 383), (100, 438) , (100, 414), (100, 35), (100, 130), (100, 143), (100, 383), (438, 414), (438, 35), (438, 130), ( 438, 143), (438, 383), (414, 35), (414, 130), (414, 143), (414, 383), (35, 130), (35, 143), (35, 383), (130, 143), (130, 383), (143, 383)

我想将每个组合保存到一个新文件名中，并在每个数字后添加字符串 "A"。

我已经尝试过逐个字符地阅读，但它不起作用。

import functools

with open ("combi2.txt", "r+") as f:
    f_read_ch=functools.partial(f.read,3)
    for ch in iter (f_read_ch,''):
        print(repr(ch))

Combi_1.txt 第133回第134话

Combi_2.txt 第133回 100安

Combi_3.txt 第133回第134话

Answer 1

给你：

import re

# collect data
raw_data = []
with open('combi2.txt', 'r') as file:
     data = file.readlines()
     raw_data.append(data[0])

# find numbers sets in text
numbers_set = re.findall('(\d+,\s\d+)', raw_data[0])

# create files
count = 0
for item in numbers_set:
    element = item.split(', ')
    file = open('Combi_' + str(count) + '.txt', 'w')
    file.write(element[0] + ' A ' + element[1] + ' A')
    count += 1

输出示例：

Combi_0.txt with 133 A 134 A inside

如何读取数字组合文件并将每个组合保存为新文件名？

how to read a file of combination of numbers and save saving each combination into a new file name?

python

file-handling