如何将数组作为 url 的参数传递并完整接收

Question

我有一个如下所示的数组：

$quantity = explode(",", $dataProducts["quantityArray"]);
$valuePrice = explode(",", $dataProducts["valuePriceArray"]);
$productsId = explode(",", $dataProducts["productsIdArray"]);

for($i=0;$i<count($productsId);$i++){ 

    $products = array('id' => $productsId[$i],
                      'price' => $valuePrice[$i],
                      'quantity' => $quantity[$i]);

}

假设向量由 4 个产品及其 ID、价格和数量组成。（之前我检查阵列是否正确武装）

$products[0] = ['id' => 4, 'price' => 20, 'quantity' => 2]

$products[1] = ['id' => 10, 'price' => 100, 'quantity' => 5]

$products[2] = ['id' => 15, 'price' => 40, 'quantity' => 4]

$products[3] = ['id' => 20, 'price' => 50, 'quantity' => 3]

我将它作为参数传递给 'success' 的 url。 但是生成url时，只有数组的第一个索引到达。

$products= http_build_query($products);

#Configure the url of response for user
$preference->back_urls = array(
            "success" => "{$url}/index.php?route=profile&data=".$products,
            "failure" => "{$url}/index.php?route=error",
            "pending" => "{$url}/index.php?ruta=pending"
);

生成的示例 url，只有数组的第一个索引：

https://www.webpage.com/index.php?route=profile&data=id=4&price=20&quantity=2

我做错了什么？

Answer 1

要将项目附加到数组，请使用以下语法：$array[] = $value

在你的例子中：

for($i=0; $i<count($productsId); $i++){ 
    $products[] = array(
        'id' => $productsId[$i],
        'price' => $valuePrice[$i],
        'quantity' => $quantity[$i]
    );
}

Answer 2

这个：

$products[0] = ['id' => 4, 'price' => 20, 'quantity' => 2];
$products[1] = ['id' => 10, 'price' => 100, 'quantity' => 5];
$products[2] = ['id' => 15, 'price' => 40, 'quantity' => 4];
$products[3] = ['id' => 20, 'price' => 50, 'quantity' => 3];
$str = http_build_query($products);
echo $str . PHP_EOL;

生成这个：

0%5Bid%5D=4&0%5Bprice%5D=20&0%5Bquantity%5D=2&1%5Bid%5D=10&1%5Bprice%5D=100&1%5Bquantity%5D=5&2%5Bid%5D=15&2%5Bprice %5D=40&2%5B数量%5D=4&3%5出价%5D=20&3%5B价格%5D=50&3%5B数量%5D=3

如果您正在寻找这样的输出：

id=4&price=20&quantity=2&id=10&price=100&quantity=5&id=15&price=40&quantity=4&id=20&price=50&quantity=3

然后这样做：

$str2 = '';

foreach($products as $product) { 
   $tmp = http_build_query($product);
   if ( ! empty($str2) ) {
      $str2 .= '&';
   }
   $str2 .= $tmp;
}
echo $str2 . "\n";

您可以将整个数组编码为 JSON base 64 编码。

$data = base64_encode(json_encode($products));
echo "http://example.com/?data=" . $data . PHP_EOL;

然后在接收端：

$products = json_decode(base64_decode($_GET['data']), true);

如何将数组作为 url 的参数传递并完整接收

How to pass an array as a parameter of url and receive it full

php

arrays

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