如何在 BigQuery 的 table 中显示时间戳类型列的时间？

Question

我有一个 table，其中有一列名为 "INTERACTION_TIMESTAMP"。

我想显示该特定列的日期和时间格式。

到目前为止，我已经尝试了以下代码：

SELECT
 USERID as UserId,
 INTERACTION_TIMESTAMP,
 EXTRACT(ISOWEEK FROM INTERACTION_TIMESTAMP) as IsoWeek,
 EXTRACT(DATE from INTERACTION_TIMESTAMP) as date,
 EXTRACT(DAYOFWEEK FROM INTERACTION_TIMESTAMP)-1 as DayOfWeek,
 PARSE_TIMESTAMP("%H", INTERACTION_TIMESTAMP, "UTC") as Time;
 CONCAT(CAST(JOURNEY_ID AS STRING),"-", CAST(JOURNEY_ACTIONID AS STRING)) as JobId,
CASE 
 WHEN INTERACTION_TYPE = 0 THEN "open"
 WHEN INTERACTION_TYPE = 1 THEN "click"
 ELSE null
END AS Open_Click
FROM
 `XXXXXXXXX.database_name`

但是，BigQuery 总是从该行代码中发出错误消息： PARSE_TIMESTAMP("%H", INTERACTION_TIMESTAMP, "UTC") as Time;

错误消息说（据我所知）PARSE_TIMESTAMP 与本网站显示的语法不匹配：PARSE_TIMESTAMP documentation

如何处理来自 INTERACTION_TIMESTAMP 的字符串，以便我可以在 BigQuery 中显示时间戳的时间值？

谢谢

Answer 1

您可以使用 EXTRACT 函数提取时间并像这样传递时区

select EXTRACT(TIME FROM CURRENT_TIMESTAMP() AT TIME ZONE 'UTC') as Time;

Answer 2

以下适用于 BigQuery 标准 SQL

而不是 PARSE_TIMESTAMP 你应该使用 FORMAT_TIMESTAMP

SELECT
 USERID as UserId,
 INTERACTION_TIMESTAMP,
 EXTRACT(ISOWEEK FROM INTERACTION_TIMESTAMP) as IsoWeek,
 EXTRACT(DATE from INTERACTION_TIMESTAMP) as date,
 EXTRACT(DAYOFWEEK FROM INTERACTION_TIMESTAMP)-1 as DayOfWeek,
 FORMAT_TIMESTAMP("%H", INTERACTION_TIMESTAMP, "UTC") as Time,
 CONCAT(CAST(JOURNEY_ID AS STRING),"-", CAST(JOURNEY_ACTIONID AS STRING)) as JobId,
CASE 
 WHEN INTERACTION_TYPE = 0 THEN "open"
 WHEN INTERACTION_TYPE = 1 THEN "click"
 ELSE null
END AS Open_Click
FROM
 `XXXXXXXXX.database_name`

如何在 BigQuery 的 table 中显示时间戳类型列的时间？

How to show time from a column of timestamp type in table at BigQuery?

google-bigquery

bigquery-standard-sql