Angular 使用最少数量的文件构建 ng? (只支持 Chrome 也可以)

Angular ng build with minimum number of files ? (supporting only Chrome is also fine)

当我构建 angular 项目时,我看到

main-es5.jsmain-es2015.js 两个文件。我只想支持 Chrome 浏览器 我怎样才能关闭构建旧的 js 文件 我想要构建时的最少文件数。

自从我升级到 8 后,我的构建也运行了两次

备注

Build time has significantly increased and i get the warning WARNING in budgets, maximum exceeded for initial.

这是我的Angular.json文件

      "optimization": true,
      "outputHashing": "none",
      "sourceMap": true,
      "extractCss": false,
      "namedChunks": false,
      "showCircularDependencies": false,
      "aot": true,
      "extractLicenses": false,
      "statsJson": false,
      "progress": true,
      "vendorChunk": false,
      "buildOptimizer": true,

浏览器列表文件

# This file is used by the build system to adjust CSS and JS output to support the specified browsers below.
# For additional information regarding the format and rule options, please see:
# https://github.com/browserslist/browserslist#queries

# You can see what browsers were selected by your queries by running:
#   npx browserslist

> 0.5%
last 2 versions
Firefox ESR
not dead
not IE 9-11 # For IE 9-11 support, remove 'not'.

编辑:在 Github

上提出功能请求

在 tsconfig.json 中有目标:"es2015" 将目标更改为 "es5" 您将获得类似 angular 7 应用程序的构建。

根据@clydin 's comment on GitHub

**browserlist** 
last 2 Chrome versions

https://browserl.ist/?q=last+2+Chrome+versions

仅创建一个最小的 chrome ES2015+ 构建