如何将方程 "x^2+x^2+2x-x-25" 中变量的空系数转换为“+1x^2+1x^2+2x-1x-25”？

Question

这是我试图修正任何数学方程变量的系数 对于 "x^2+x^2+2x-x-25" 等相同变量的总和系数为“+1x^2+1x^2+2x-1x-25”，然后求和为“2x^2+x-25”，请注意我用另一种方法完成了求和过程。

private static String fixCoeff(String equ)
{
    equ=equ.toLowerCase();//change equation variables to lower case
    equ=equ.trim();//remove white spaces
    String []characters={"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
    int index=-1;
    String fixedCoeff="";
    for (int i = 0; i < characters.length; i++)
    {
        if(!equ.contains(characters[i]))
        {
            continue;
        }
        //if a not found in equ i++ 
        //if true execute this
        while(equ.indexOf(characters[i],++index)!=-1)
        {


            index=equ.indexOf(characters[i]);
            if(index==0)
            {
                fixedCoeff+="+1"+equ;
                equ=fixedCoeff;
                index=2;
                break;

            }
            else
            {

                if (equ.charAt(index-1)=='+'||equ.charAt(index-1)=='-')
                {
                    fixedCoeff=equ.substring(-1,index-1);
                    fixedCoeff+="1"+equ.substring(index-1,equ.length()-1);
                    equ=fixedCoeff;
                    index++;
                    break;
                }

            }

        //  if (index==equ.length()-1) {//if we found last element in equ is a variable
                //break;
            //}
        }//end while

    }//end for loop 


    return equ;

}//end fixCoeff

输入个案：

1. 一个
2. x
3. x^2
4. x^2+x^2

输出案例：

1. +1a
2. +1x
3. +1x^2
4. +1x^2+1x^2

Answer 1

您可以像这样使用 String.replaceAll() 更轻松地完成此操作：

for (int i = 0; i < characters.length; i++)
{
    if(!equ.contains(characters[i]))
    {
        continue;
    }
    equ = equ.replaceAll(("(?<!\d)" + characters[i]), ("1" + characters[i]));
}
if(!equ.startsWith("-") && !equ.startsWith("+"))
{
    equ = "+" + equ;
}

这会将前面没有数字的字符替换为 1x（或任何当前字符）。这使用带有负后视的正则表达式来确保字符前面没有数字，然后它将替换为 1（字符）。

这是一个独立的例子：

String line = "x-x^2+3x^3";
line = line.replaceAll("(?<!\d)x", "1x");
System.out.println("" + line);

这将输出 1x-1x^2+3x^3.

Answer 2

只是加起来@brso05 的回答，

这是另一种方法：

    String s ="x^2+x^2+2x-x-25";
    s=s.replaceAll("(?<!\d)([a-z])", "1");    // <-- replaces any lower letters with 1 concatanted with the same letter
    if(!s.startsWith("-")){
        s="+"+s;  //<-- if the first character is not negative add a + to it.
    }
    System.out.println(s);

输出：

+1x^2+1x^2+2x-1x-25