java GMT 日期时间解析

java GMT datetimeparse

我有如下字符串

Fri May 31 2019 05:08:40 GMT-0700 (PDT)

我想将其转换为类似 yyyy-MM-dd 的格式。

我试过了。

String date1 = "Fri May 31 2019 05:08:40 GMT-0700 (PDT)";
DateTimeFormatter f = DateTimeFormatter.ofPattern( "E MMM dd HH:mm:ss z uuuu" ).withLocale( Locale.US );

ZonedDateTime zdt = ZonedDateTime.parse( date1 , f );
LocalDate ld = zdt.toLocalDate();
DateTimeFormatter fLocalDate = DateTimeFormatter.ofPattern( "yyyy-MM-dd" );
String output = ld.format( fLocalDate ) ;

我遇到错误:

Exception in thread "main" java.time.format.DateTimeParseException: Text 
'Fri May 31 2019 05:08:40 GMT-0700 (PDT)' could not be parsed at index 13
at java.time.format.DateTimeFormatter.parseResolved0(Unknown Source)
at java.time.format.DateTimeFormatter.parse(Unknown Source)
at java.time.ZonedDateTime.parse(Unknown Source)

你格式化程序的模式是错误的。缺少年份 ("yyyy") 且时区不匹配。要匹配它,您需要同时使用 zZ 您还需要为 GMT 添加不匹配的文本,例如 "'GMT'Z (z)".

试试这个:

"E MMM dd yyyy HH:mm:ss 'GMT'Z (z)"

如您所见here,您可以使用以下模式:

public static void main(String[] args) throws Exception {
    String date1 = "Fri May 31 2019 05:08:40 GMT-0700 (PDT)";
    DateTimeFormatter f = DateTimeFormatter.ofPattern( "EEE MMM dd yyyy HH:mm:ss 'GMT'Z '('z')'" ).withLocale( Locale.US );

    ZonedDateTime zdt = ZonedDateTime.parse( date1 , f );
    LocalDate ld = zdt.toLocalDate();
    DateTimeFormatter fLocalDate = DateTimeFormatter.ofPattern( "yyyy-MM-dd" );
    String output = ld.format( fLocalDate ) ;
    System.out.println(output);
}

输出:

2019-05-31

由于您只需要 yyyy-MM-dd 格式的日期,请尝试以下代码:

   String date1 = "Fri May 31 2019 05:08:40 GMT-0700";

   //this format is good enough to read required data from your String
   DateFormat df1 = new SimpleDateFormat("EEE MMM dd yyyy HH:mm:ss");

   //format you require as final output
   DateFormat df2 = new SimpleDateFormat("yyyy-MM-dd");

   //convert String to date ( with required attributes ) and then format to target
   System.out.println(df2.format(df1.parse(date1)));