Php 将更多数组保存到 MySQL

Question

我正在尝试使用 PHP 在 MySQL 数据库中保存数组。

代码仅插入第一行，如果我有 5 个元素的 array，它只插入第一个元素，其他元素和 4 个不为我保存它们。

谁能告诉我哪里错了？

非常感谢。

<?php

//getting user values

$day = $_POST['Day'];
$nDay = $_POST['n_Day'];
$fieldOne = $_POST['Field_one'];
$fieldTwo = $_POST['Field_two'];
$timeOne = $_POST['Time_one'];
$timeTwo = $_POST['Time_two'];
$idR = $_POST['id_ristorante'];

$day_array = explode(",",$day);
$nDay_array = explode(",",$nDay);
$timeOne_array = explode(",",$timeOne);
$timeTwo_array = explode(",",$timeTwo);

$len = count($day_array and $nDay_array and $timeOne_array and $timeTwo_array);

$output=array();

//require database
require_once('db.php');

//checking if email exists
$conn=$dbh->prepare('SELECT id_ristorante FROM Orari WHERE id_ristorante=:idR');
$conn->bindParam(':idR', $idR, PDO::PARAM_STR);

$conn->execute();

//results
if($conn->rowCount() !==0){
    $output['isSuccess'] = 0;
    $output['message'] = "Orario già inserito";
} else {

     for($i=0;$i<$len;$i++){

         $day = $day_array[$i];
         $nDay = $nDay_array[$i];
         $timeOne = $timeOne_array[$i];
         $timeTwo = $timeTwo_array[$i];

        $conn=$dbh->prepare('INSERT INTO Orari (Day, n_Day, Field_one, Field_two, Time_one, Time_two, id_ristorante) VALUES (?,?,?,?,?,?,?)');
        //encrypting the password

        $conn->bindParam(1,$day);
        $conn->bindParam(2,$nDay);
        $conn->bindParam(3,$fieldOne);
        $conn->bindParam(4,$fieldTwo);
        $conn->bindParam(5,$timeOne);
        $conn->bindParam(6,$timeTwo);
        $conn->bindParam(7,$idR);


        $conn->execute();
        if($conn->rowCount() == 0) {
            $output['isSuccess'] = 0;
            $output['message'] = "Errore, riprova.";
        } elseif($conn->rowCount() !==0){
            $output['isSuccess'] = 1;
            $output['message'] = "Orari salvati!";

        }
    } 
}
echo json_encode($output);

?>

Answer 1

当您尝试对多个数组执行 count 时：

$len = count($day_array and $nDay_array and $timeOne_array and $timeTwo_array);

and 导致对数组进行布尔值计算，因此最终分配给 $len 的值为 1，这就是循环仅执行一次并且仅将第一个元素插入 DB 的原因。

如果所有数组的长度都相同，您应该只计算其中的一个：

$len = count($day_array)

更好的做法是对它们进行计数，然后为 $len 分配最小值

Answer 2

更改此行

$len = count($day_array and $nDay_array and $timeOne_array and $timeTwo_array);

至

$len = count($day_array) + count($nDay_array) + count($timeOne_array) + count($timeTwo_array);

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