无法应用参数化柯里化函数

Question

我有一个函数，其定义如下：

def expectMsgPF[T](max: Duration = Duration.Undefined, hint: String = "")(f: PartialFunction[Any, T]): T = {

当我这样调用时：

val res1 = listener1.expectMsgPF(1.second)

res1是函数吗？

我想这样写：

 val res1 = listener1.expectMsgPF(1.second) _
 val res2 = listener2.expectMsgPF(1.second)
 Then("it should contain `Kafka and SAP are offline`")
 res1 {
    case status: ServerStatus =>
    status.health should be(ServersOffline)
  }

但是不行。

Answer 1

要使 res1 { case status: ServerStatus => status.health should be(ServersOffline) } 工作，请尝试通过向 expectMsgPF[T] 提供类型参数 T 来帮助编译器，就像这样

val res1 = listener1.expectMsgPF[Assertion](1.second) _

这使得 res1 确实是

类型的函数

PartialFunction[Any, Assertion] => Assertion

无法应用参数化柯里化函数

Unable to apply parameterised curried function

scala

currying