如何将 SFSafariViewController 与 SwiftUI 一起使用？

Question

我正在尝试从 NavigationButton 呈现 SFSafariViewController，但我不确定如何使用 SwiftUI 来实现。

在 UIKit 中，我会这样做：

let vc = SFSafariViewController(url: URL(string: "https://google.com"), entersReaderIfAvailable: true)
    vc.delegate = self

    present(vc, animated: true)

Answer 1

SFSafariViewController 是一个 UIKit 组件，因此您需要将其设为 UIViewControllerRepresentable.

有关如何将 UIKit 组件桥接到 SwiftUI 的更多详细信息，请参阅 Integrating SwiftUI WWDC 19 视频。

struct SafariView: UIViewControllerRepresentable {

    let url: URL

    func makeUIViewController(context: UIViewControllerRepresentableContext<SafariView>) -> SFSafariViewController {
        return SFSafariViewController(url: url)
    }

    func updateUIViewController(_ uiViewController: SFSafariViewController,
                                context: UIViewControllerRepresentableContext<SafariView>) {

    }

}

警告说明：SFSafariViewController 旨在显示在另一个视图控制器之上，而不是推送到导航堆栈中。

它还有一个导航栏，这意味着如果你按下视图控制器，你会看到两个个导航栏。

如果以模态方式呈现，它似乎可以工作 - 虽然它有问题。

struct ContentView : View {

    let url = URL(string: "https://www.google.com")!

    var body: some View {
        EmptyView()
        .presentation(Modal(SafariView(url:url)))
    }
}

看起来像这样：

我建议通过 UIViewRepresentable 协议将 WKWebView 移植到 SwiftUI，并使用它代替。

Answer 2

这是使用 WKWebView 的答案，但它看起来仍然不正确。

struct SafariView: UIViewRepresentable {

    let url: String

    func makeUIView(context: Context) -> WKWebView {
        return WKWebView(frame: .zero)
    }

    func updateUIView(_ view: WKWebView, context: Context) {
        if let url = URL(string: url) {
            let request = URLRequest(url: url)
            view.load(request)
        }
    }
}

Answer 3

, .presentation(Modal()) was removed by iOS 13's release 的补充。此代码应该有效（在 Xcode 11.3、iOS 13.0 - 13.3 中测试）：

import SwiftUI
import SafariServices

struct ContentView: View {
    // whether or not to show the Safari ViewController
    @State var showSafari = false
    // initial URL string
    @State var urlString = "https://duckduckgo.com"

    var body: some View {
        Button(action: {
            // update the URL if you'd like to
            self.urlString = "https://duckduckgo.com"
            // tell the app that we want to show the Safari VC
            self.showSafari = true
        }) {
            Text("Present Safari")
        }
        // summon the Safari sheet
        .sheet(isPresented: $showSafari) {
            SafariView(url:URL(string: self.urlString)!)
        }
    }
}

struct SafariView: UIViewControllerRepresentable {

    let url: URL

    func makeUIViewController(context: UIViewControllerRepresentableContext<SafariView>) -> SFSafariViewController {
        return SFSafariViewController(url: url)
    }

    func updateUIViewController(_ uiViewController: SFSafariViewController, context: UIViewControllerRepresentableContext<SafariView>) {

    }

}

Answer 4

有时答案就是不使用 SwiftUI！这在 UIKit 中得到了很好的支持，我只是做了一个简单的 UIKit 桥接，所以我可以从 SwiftUI 中在一行中调用 SafariController，如下所示：

HSHosting.openSafari(url:URL(string: "https://hobbyistsoftware.com")!)

我只是用 HSHostingController 替换了应用顶层的 UIHostingController

（注意 - 此 class 还允许您控制模式的呈现样式）

//HSHostingController.swift
import Foundation
import SwiftUI
import SafariServices

class HSHosting {
    static var controller:UIViewController?
    static var nextModalPresentationStyle:UIModalPresentationStyle?

    static func openSafari(url:URL,tint:UIColor? = nil) {
        guard let controller = controller else {
            preconditionFailure("No controller present. Did you remember to use HSHostingController instead of UIHostingController in your SceneDelegate?")
        }

        let vc = SFSafariViewController(url: url)  

        vc.preferredBarTintColor = tint
        //vc.delegate = self

        controller.present(vc, animated: true)
    }
}

class HSHostingController<Content> : UIHostingController<Content> where Content : View {

    override init(rootView: Content) {
        super.init(rootView: rootView)

        HSHosting.controller = self
    }

    @objc required dynamic init?(coder aDecoder: NSCoder) {
        fatalError("init(coder:) has not been implemented")
    }

    override func present(_ viewControllerToPresent: UIViewController, animated flag: Bool, completion: (() -> Void)? = nil) {

        if let nextStyle = HSHosting.nextModalPresentationStyle {
            viewControllerToPresent.modalPresentationStyle = nextStyle
            HSHosting.nextModalPresentationStyle = nil
        }

        super.present(viewControllerToPresent, animated: flag, completion: completion)
    }

}

在场景委托中使用 HSHostingController 而不是 UIHostingController 像这样：

    // Use a HSHostingController as window root view controller.
    if let windowScene = scene as? UIWindowScene {
        let window = UIWindow(windowScene: windowScene)

        //This is the only change from the standard boilerplate
        window.rootViewController = HSHostingController(rootView: contentView)

        self.window = window
        window.makeKeyAndVisible()
    }

那么当你想打开SFSafariViewController时，只需调用：

HSHosting.openSafari(url:URL(string: "https://hobbyistsoftware.com")!)

例如

Button(action: {
    HSHosting.openSafari(url:URL(string: "https://hobbyistsoftware.com")!)
}) {
    Text("Open Web")
}

更新：请参阅 this gist 以了解具有附加功能的扩展解决方案

Answer 5

在 SwiftUI 中是可能的，甚至保留默认外观，但您需要公开一个 UIViewController 才能使用。从定义一个 SwiftUI UIViewControllerRepresentable 开始，它传递了一个布尔绑定和一个激活处理程序：

import SwiftUI

struct ViewControllerBridge: UIViewControllerRepresentable {
    @Binding var isActive: Bool
    let action: (UIViewController, Bool) -> Void

    func makeUIViewController(context: Context) -> UIViewController {
        return UIViewController()
    }

    func updateUIViewController(_ uiViewController: UIViewController, context: Context) {
        action(uiViewController, isActive)
    }
}

然后，给你计划显示 SafariVC 的小部件从一个状态属性确定它是否应该显示，然后添加这个桥以显示 VC 当状态变化。

struct MyView: View {
    @State private var isSafariShown = false

    var body: some View {
        Button("Show Safari") {
            self.isSafariShown = true
        }
        .background(
            ViewControllerBridge(isActive: $isSafariShown) { vc, active in
                if active {
                    let safariVC = SFSafariViewController(url: URL(string: "https://google.com")!)
                    vc.present(safariVC, animated: true) {
                        // Set the variable to false when the user dismisses the safari VC
                        self.isSafariShown = false
                    }
                }
            }
            .frame(width: 0, height: 0)
        )
    }
}

请注意，我给 ViewControllerBridge 一个宽度和高度为零的固定框架，这意味着您可以将它放在视图层次结构中的任何位置，并且不会对您的 UI。

--雅库布

Answer 6

使用BetterSafariView，你可以在SwiftUI中轻松呈现SFSafariViewController。它按照 Apple 的预期运行良好，不会丢失其原始的推送过渡和 swipe-to-dismiss 手势。

用法

.safariView(isPresented: $presentingSafariView) {
    SafariView(url: URL("https://github.com/")!)
}

示例

import SwiftUI
import BetterSafariView

struct ContentView: View {
    
    @State private var presentingSafariView = false
    
    var body: some View {
        Button("Present SafariView") {
            self.presentingSafariView = true
        }
        .safariView(isPresented: $presentingSafariView) {
            SafariView(
                url: URL(string: "https://github.com/stleamist/BetterSafariView")!,
                configuration: SafariView.Configuration(
                    entersReaderIfAvailable: false,
                    barCollapsingEnabled: true
                )
            )
        }
    }
}

Answer 7

上面的

None 对我有用，因为我试图在按钮列表中显示 SFSafariViewController。我最终使用了绑定。

在您的视图控制器中进行绑定：

class YourViewController: UIViewController {
    private lazy var guideHostingViewController = UIHostingController(rootView: UserGuideView(presentUrl: presentBinding))

    @objc private func showWebsite() {
        let navVC = UINavigationController(rootViewController: guideHostingViewController)
        present(navVC, animated: true, completion: nil)
    }
    
    private var presentBinding: Binding<URL> {
        return Binding<URL>(
            get: {
                return URL(string: "https://www.percento.app")!
            },
            set: {
                self.guideHostingViewController.present(SFSafariViewController(url: [=10=]), animated: true, completion: nil)
            }
        )
    }
}

SwiftUI 列表：

struct UserGuideView: View {
    private let guidePages: [SitePage] = [.multiCurrency, .stockSync, .dataSafety, .privacy]
    @Binding var presentUrl: URL

    var body: some View {
        VStack(alignment: .leading) {
            ForEach(guidePages) { page in
                Button(action: {
                    presentUrl = page.localiedContentUrl
                }) {
                    Text(page.description)
                        .foregroundColor(Color(UIColor.label))
                        .modifier(UserGuideRowModifier(icon: .init(systemName: page.systemIconName ?? "")))
                }
            }
            Spacer()
        }
        .padding()
        .navigationBarTitle(NSLocalizedString("User Guide", comment: "User Guide navigation bar"))
    }
}

如何将 SFSafariViewController 与 SwiftUI 一起使用？

How do I use SFSafariViewController with SwiftUI?

safari

ios

swift

swiftui

用法

示例