我如何将字符转换为 R 中的二进制值

Question

我有一个带有 * 和 - 我想将 * 转换为 1 和 - 为 0 但我不知道该怎么做的数据框

这是我的数据框

> head(Patient_036)
       Driver SNV_Organoid_036 INDEL_Organoid_036 Deletion_Organoid_036
ABCB1       *                -                  *                     -
ACVR1B      *                *                  *                     -
ACVR2A      *                *                  -                     -
APC         *                -                  *                     -
ARID1A      *                -                  *                     -
ARID1B      *                *                  -                     -

有什么帮助吗？

Answer 1

Patient_036[Patient_036 == "*"] <- 1
Patient_036[Patient_036 == "-"] <- 0

数据：

Patient_036 <- structure(list(Driver = c("1", "1", "1", "1", "1", "1"), SNV_Organoid_036 = c("0", 
"1", "1", "0", "0", "1"), INDEL_Organoid_036 = c("1", "1", "0", 
"1", "1", "0"), Deletion_Organoid_036 = c("0", "0", "0", "0", 
"0", "0")), row.names = c("ABCB1", "ACVR1B", "ACVR2A", "APC", 
"ARID1A", "ARID1B"), class = "data.frame")

如果您的数据框包含 factors，您可能首先需要 df[] <- lapply(df, as.character)。如果您在读入数据时添加 stringsAsFactors = FALSE 或等效内容，则没有必要这样做。

我如何将字符转换为 R 中的二进制值

How I convert characters to binary values in R

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binary-data