MySQL

Question

我有 2 个 tables 事务和 trans_comments 当我进行内部连接时 returns 第一个条目，我想做的是显示地址和状态表交易 table 和最后输入的评论以及来自 trans_comments table

的日期

这是我得到的

SELECT t.address, t.status, c.time, c.comment
FROM transactions t
INNER JOIN trans_comments c ON c.transactionId = t.transactionId
WHERE STATUS LIKE  '%Listing%'
GROUP BY t.address DESC

我错过了什么？

这是 table 的布局：

`transactions` (
  `transactionId` int(11) NOT NULL AUTO_INCREMENT,
  `address` varchar(45) NOT NULL,
  `listing_agent` varchar(65) DEFAULT NULL,
  `status` varchar(45) NOT NULL,
  `notes` varchar(100) DEFAULT NULL,
  `file_type` varchar(25) NOT NULL,
  `system` varchar(25) DEFAULT NULL,
  PRIMARY KEY (`transactionId`)      
)ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=41 ;

`trans_comments` (
  `commId` int(11) NOT NULL AUTO_INCREMENT,
  `transactionId` int(11) NOT NULL,
  `comment` blob NOT NULL,
  `commentBy` varchar(45) NOT NULL,
  `time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
  PRIMARY KEY (`commId`),
  KEY `transactionId` (`transactionId`)
)ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=101 ;

谢谢

Answer 1

SELECT t.address, t.status, c.time, c.comment
FROM transactions t
INNER JOIN 
  (SELECT c1.*
   FROM trans_comments c1
   LEFT JOIN trans_comments c2
   ON c1.transactionId = c2.transactionId 
     AND c1.`time` < c2.`time` 
   WHERE c2.commId IS NULL
  ) c 
ON c.transactionId = t.transactionId
WHERE STATUS LIKE  '%Listing%'

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