Symfony 4.3.1 和 FosUserBundle 2.1.2 的问题

Issues with Symfony 4.3.1 and FosUserBundle 2.1.2

对于一个新项目,我使用 Symfony 4.3 和 FosUserBundle 2.1。我成功安装了这个包,但是当我尝试使用它时,我遇到了一些问题。

当我尝试访问登录页面 (http://127.0.0.1:8000/login) 时,它运行良好。但是,在注册页面上我遇到了一些错误:

Property "superAdmin" does not exist in class "App\Entity\User"

我尝试在我的用户实体中添加属性 superAdmingroup(我不知道这是否是个好主意)。页面显示正确。现在,当我尝试提交注册表时,出现 4 个错误(所有字段都已填写):

FosUserBundle 与 Symfony 4.3 兼容吗?如何解决这些问题?有其他选择吗?

解决方法如下: ==> 您必须在您的实体用户中添加 $group 和 $superAdmin,因此您可以将 $group 设置为 nullable=true,并且 $superAdmin 是布尔值,您可以将其设置为 true 或 false。 注意:您必须重命名列组,因为该组是 mysql 中的保留字,我在构造函数中设置了这些,因此您可以以自定义形式将它们设置为喜欢:

<?php
// src/AppBundle/Entity/User.php

namespace App\Entity;

use FOS\UserBundle\Model\User as BaseUser;
use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;

/**
 * @ORM\Entity
 * @ORM\Table(name="fos_user")
 */
class User extends BaseUser
{
    /**
     * @ORM\Id
     * @ORM\Column(type="integer")
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    protected $id;

    /**
     * @ORM\Column(type="string", nullable=true)
     */
    protected $prenom;
    /**
     * @ORM\Column(type="boolean")
     */
    protected $superAdmin;
    /**
     * @ORM\Column(name="giroupy", type="string", nullable=true)
     */
    protected $group;

    public function __construct()
    {
        parent::__construct();
        $this->superAdmin = false;
        $this->groups = new ArrayCollection();
        // your own logic
        if (empty($this->registerDate)) {
            $this->registerDate = new \DateTime();
        }
    }

    public function getId(): ?int
    {
        return $this->id;
    }

    public function getPrenom(): ?string
    {
        return $this->prenom;
    }

    public function setPrenom(string $prenom): self
    {
        $this->prenom = $prenom;

        return $this;
    }

    public function getGroup(): ?string
    {
        return $this->group;
    }

    public function setGroup(?string $group): self
    {
        $this->group = $group;

        return $this;
    }

    public function getSuperAdmin(): ?bool
    {
        return $this->superAdmin;
    }


    public function setSuperAdmin($superAdmin): self
    {
        $this->superAdmin = $superAdmin;

        return $this;
    }
}

所以在设置密码后,您必须为事件 SUBMIT 挂钩 formEvent 以获取实体用户,例如:

<?php
// src/AppBundle/Form/RegistrationType.php

namespace App\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\Form\Extension\Core\Type\EmailType;
use Symfony\Component\Form\FormEvent;
use Symfony\Component\Form\FormEvents;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;

class RegistrationType extends AbstractType
{
    private $userPassWordInterface;
    public function __construct(
        UserPasswordEncoderInterface $userPassWordInterface
    )
    {
        $this->userPassWordInterface = $userPassWordInterface;
    }
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('prenom')
        ->addEventListener(
                FormEvents::SUBMIT,
                [$this, 'onSubmit']
            )
        ;
    }

    public function onSubmit(FormEvent $event)
    {
        $user = $event->getData();
        $form = $event->getForm();

        if (!$user) {
            return;
        }
        $passWord = $this->userPassWordInterface->encodePassword($user, $user->getPlainPassword());
        $user->setPassWord($passWord);

        // checks whether the user has chosen to display their email or not.
        // If the data was submitted previously, the additional value that
        // is included in the request variables needs to be removed.

    }

    public function getParent()
    {
        return 'FOS\UserBundle\Form\Type\RegistrationFormType';
    }

    public function getBlockPrefix()
    {
        return 'app_user_registration';
    }

    // For Symfony 2.x
    public function getName()
    {
        return $this->getBlockPrefix();
    }
}

安全方面如:

security:
    # https://symfony.com/doc/current/security.html#where-do-users-come-from-user-providers

    encoders:
        App\Entity\User: bcrypt

    role_hierarchy:
        ROLE_SUPER_ADMIN: ROLE_ADMIN
        ROLE_ADMIN:       ROLE_USER

    providers:
        fos_userbundle:
            id: fos_user.user_provider.username
    firewalls:
        dev:
            pattern: ^/(_(profiler|wdt)|css|images|js)/
            security: false
        main:
            pattern: ^/
            form_login:
                provider: fos_userbundle
                csrf_token_generator: security.csrf.token_manager

            logout:       true
            anonymous:    true

    # Easy way to control access for large sections of your site
    # Note: Only the *first* access control that matches will be used
    access_control:
        - { path: ^/login$, role: IS_AUTHENTICATED_ANONYMOUSLY }
        - { path: ^/register, role: IS_AUTHENTICATED_ANONYMOUSLY }
        - { path: ^/resetting, role: IS_AUTHENTICATED_ANONYMOUSLY }
        - { path: ^/admin/, role: ROLE_ADMIN }

所以在你的包中设置表单登录后:config/packages/fos_user.yaml

fos_user:
    db_driver: orm # other valid values are 'mongodb' and 'couchdb'
    firewall_name: main
    user_class: App\Entity\User
    registration:
        form:
            type: App\Form\RegistrationType
    from_email:
        address: "%mailer_user%"
        sender_name: "%mailer_user%"

不要忘记加载路由:config/routes/fos_user.yaml

fos_user:
    resource: "@FOSUserBundle/Resources/config/routing/all.xml"

问题就简单多了。 FOSUserBundle 仍然与 Symfony 4.3 兼容,只是不适用于 4.3 validator 组件自动验证设置,默认开启:

framework:
    validation:
        email_validation_mode: html5

        # Enables validator auto-mapping support.
        # For instance, basic validation constraints will be inferred from Doctrine's metadata.
        auto_mapping:       # <----- REMOVE THIS THIS
            App\Entity\: [] # <-------- AND THIS

它解决了我的问题,但这也意味着您需要手动设置验证规则。