LDAP：清空 binddn"" 并且身份验证类型从 none 变得简单

Question

正在 Spring MVC 和 JPA 中开发具有 Spring 安全性的应用程序。现在通过 LDAP 集成 OUD（Oracle 统一目录）。用户身份验证时，OUD 日志文件中来自 LDAP 的响应是

CONNECT conn=909681 从 ******* 到 *******:1636 协议=LDAPS

绑定请求 conn=909681 op=0 msgID=1 type=SIMPLE dn="" version=3

BindRES conn=909681 op=0 msgID=1 result=1 message="The directory server could not find a network group for the bind dn "” 因为客户端连接不符合任何网络组的连接条件."

DISCONNECT conn=909681 原因="Client Disconnect"

security.xml 文件

中应用程序和 LDAP 之间的映射

<bean id="contextSource" class="org.springframework.security.ldap.DefaultSpringSecurityContextSource">
    <constructor-arg value="ldaps://192.168.0.182:1636/o=company"/>
    <property name="userDn" value="cn=userid,o=company,ou=groups"/>
    <property name="password" value="password"/>
</bean>

<bean id="ldapAuthProvider" class="org.springframework.security.ldap.authentication.LdapAuthenticationProvider" >
     <constructor-arg>
          <bean class="in.web.service.impl.CustomLdapBindAuthenticator">
               <constructor-arg ref="contextSource"/>
               <property name="userDnPatterns">
                   <list>
                       <value>cn={0},ou=groups</value>
                   </list>
               </property>
           </bean>
     </constructor-arg>
     <constructor-arg>
           <bean class="in.web.service.impl.CustomLdapUserAuthoritiesPopulator">
           </bean>
     </constructor-arg>     
 </bean>

CustomLdapBindAuthenticator 中的代码

public LdapUserDetails search(String cn) throws Exception {
        Hashtable env = new Hashtable();
        String sp = "com.sun.jndi.ldap.LdapCtxFactory";
        env.put(Context.INITIAL_CONTEXT_FACTORY, sp);

        String [] urls = contextSource.getUrls();
        for(String url: urls){
            System.out.println("ldapurls="+url);
        }
        env.put(Context.PROVIDER_URL, urls[0]);

        DirContext dctx = new InitialDirContext(env);

        String base = "ou=groups,o=company";
        System.out.println("BASE DN="+base);

        SearchControls sc = new SearchControls();
        String[] attributeFilter = {"cn", "fullName", "mail", "l", "mobile"};
        sc.setReturningAttributes(attributeFilter);
        sc.setSearchScope(SearchControls.SUBTREE_SCOPE);

        String filter = "(&(cn="+cn+")(objectClass=*))";

        NamingEnumeration results = dctx.search(base, filter, sc);
        LdapUserDetails user = new LdapUserDetails();
        while (results.hasMore()) {
            SearchResult sr = (SearchResult) results.next();
            Attributes attrs = sr.getAttributes();

            user.setCn(getAttribute(attrs, "cn"));
            user.setFullName(getAttribute(attrs, "fullName"));
            user.setMail(getAttribute(attrs, "mail"));
            user.setMobile(getAttribute(attrs, "mobile"));
            user.setLocation(getAttribute(attrs, "l")); 
        }
        dctx.close();
        return user;
        }

Pl。帮我解决问题

我没有提到身份验证这么简单。从我在日志文件

type=simple

为什么我得到 dn=""

提前致谢

Answer 1

默认身份验证是 "simple Bind"，这意味着 DN 和密码。您没有在环境 env 中设置任何凭据，因此 JNDI 默认尝试执行匿名绑定，即空 DN 和密码。

LDAP：清空 binddn"" 并且身份验证类型从 none 变得简单

LDAP: Empty binddn"" and Authentication type becomes simple from none

oracle

spring-security

oracle11g

ldap

spring-security-ldap