如何在将 SUM() 用于另一个日期的子句中按日期使用 MIN()？

Question

我需要找到所有在 2017 年有第一笔订单的客户并汇总他们在 2018 年的收入。我在 SQL 条款中尝试这样做时遇到问题。

在我的 table 中，我有 3 个客户，其中 2 个在 2017-05-23 首次订购，1 个在 2016-06-23 首次订购。所以我想过滤掉那个在 2016 年订购的客户。在 table 中，我有字段：客户、收入、order_date。

这是我在 MySQL:

select client as 'Clients first order in 2017',
       SUM(income) as 'Sum of income in 2018'  
from orders
where YEAR(order_date) = 2018
  and (select client, order_date
       from orders
       group by client
       having min(year(order_date)) = 2017)
order by client

我希望能把2017年第一次下单的所有客户都汇总起来，总结一下他们2018年的收入

Answer 1

使用条件聚合：

Select client as 'Clients first order in 2017', 
        SUM(CASE WHEN YEAR(order_date) = 2018 
                 THEN income 
                 ELSE 0 
            END) as 'Sum income in 2018'  
FROM orders
GROUP BY client
HAVING MIN (YEAR(order_date)) = 2017
order by client

Answer 2

试试这个-

SELECT 
client as 'Clients first order in 2017', 
SUM(income)  as 'Sum of income in 2018'
FROM orders 
WHERE client IN
(
    SELECT client 
    FROM orders 
    GROUP BY client
    HAVING MIN(YEAR(order_date)) = 2017
)
AND YEAR(order_date) = 2018
GROUP BY client

如何在将 SUM() 用于另一个日期的子句中按日期使用 MIN()？

How to use MIN() by date in a clause that uses SUM() for another date?

mysql

sql

min

having