如何按一列排序，但根据非数字的不同列进行排名？

Question

我有四列要排名。他们需要按员工 ID 分组，然后按订单号从低到高列出。然后，当一切都井井有条时，我真的在努力获得城市在该顺序中的排名。如果同一个员工在同一个城市中依次列出，那么我希望那些排名相同的城市。

下面是 table 的示例。顺序是对的，但是排名不是我想做的。

Name            Employee_ID     Order_Number     City       Rank   
John               1                1            Boston       1  
John               1                2            Boston       2  
Will               2                1            Peabody      1  
Will               2                2            Weston       2   
Will               2                3            Newton       3



select Name, Employee_ID, Order_Number, City,
dense_rank() over(partition by Employee_ID order by Order_Number) as rank
from #Employee

我实际想要的结果是：

Name            Employee_ID     Order_Number     City       Rank   
John               1                1            Boston       1  
John               1                2            Boston       1  
Will               2                1            Boston       1  
Will               2                2            Weston       2   
Will               2                3            Newton       3

然后我最终会删除重复的城市以结束：

Name            Employee_ID     Order_Number     City       Rank   
John               1                1            Boston       1  
Will               2                1            Boston       1  
Will               2                2            Weston       2   
Will               2                3            Newton       3

Answer 1

您可以尝试使用以下脚本来获得所需的输出。

SELECT Name, Employee_ID, Order_Number, City ,
ROW_NUMBER() OVER (PARTITION BY Employee_ID ORDER BY Order_Number) rank
(
    select Name, Employee_ID, Order_Number, City,
    dense_rank() over(partition by Employee_ID,city order by Order_Number) as rank
    from #Employee
)A
WHERE rank = 1

结果集的输出是-

Name    Employee_ID Order_Number    City    rank
John    1           1               Boston  1
Will    2           1               Peabody 1
Will    2           2               Weston  2
Will    2           3               Newton  3

检查 Fiddle 上脚本的输出。

Answer 2

您可以使用LAG()检查之前的城市是否相同。如果前一个城市不同或为空，那么我们按原样进行排名，如果城市相同，那么排名 - 1 给我们的数字与上面的行相同。 Demo

with cte as (select Name, Employee_ID, Order_Number, City,
dense_rank() over (partition by Employee_ID order by Order_Number) as rank,
lag(City) over (partition by Employee_ID order by Order_Number) as previousCity
from #Employee)
select 
    Name, Employee_ID, Order_Number, City,
    case when previousCity = city then rank - 1
         else rank end as rank
from cte

如何按一列排序，但根据非数字的不同列进行排名？

How to order by one column, but rank based on a different column that is not numeric?

sql-server

ranking-functions