从 URL 中提取特定字符串

Question

我想从中提取一些字符串 url

https://s3-ap-southeast-1.amazonaws.com/mtpdm/2019-06-14/12-14/1001_1203_20190614120605_5dd404.jpg

我想提取 2019-06-14，我该如何使用 java？

Answer 1

使用正则表达式来实现这个以获得日期 2019-06-14,

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class ExtractDateFromURL {

     public static void main(String []args) {
        String URL = "https://s3-ap-southeast-1.amazonaws.com/mtpdm/2019-06-14/12-14/1001_1203_20190614120605_5dd404.jpg";

        Pattern pattern = Pattern.compile("(\d{4}-\d{2}-\d{1,2})");
        Matcher matcher = pattern.matcher(URL);

        if (matcher.find()) {
            System.out.println(matcher.group(1)); // Do what you need to do with the result
        }
     }
}

输出

2019-06-14

要获得 12-14，您可以使用以下正则表达式，

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class ExtractDateFromURL {

     public static void main(String []args){
        String URL = "https://s3-ap-southeast-1.amazonaws.com/mtpdm/2019-06-14/12-14/1001_1203_20190614120605_5dd404.jpg";

        Pattern pattern = Pattern.compile("/(\d{1,2}-\d{1,2}-\d{4}|\d{1,2}-\d{1,2})");
        Matcher matcher = pattern.matcher(URL);

        if (matcher.find()) {
            System.out.println(matcher.group(1));
        }
     }
}

输出

12-14

从 URL 中提取特定字符串

Extract specific string from URL

java

string

url

text-extraction