如何将字符串切成对

Question

对于我正在做的项目，我需要根据输入进行配对，但我不知道如何做，我需要一些帮助。
怎么样：

2209222717080109

我希望它变成这样：

["22","09","22","27","17","08","01","09"]

Answer 1

input = "2209222717080109"
input.chars.each_slice(2).map(&:join)
["22", "09", "22", "27", "17", "08", "01", "09"]

Answer 2

Convert it to a string, convert that into an array of characters, then take each consecutive slice of two characters, and join each of those slices一起:

2209222717080109.to_s.chars.each_slice(2).map(&:join)
#=> ["22", "09", "22", "27", "17", "08", "01", "09"]

Answer 3

"2209222717080109".scan /../
  #=> ["22", "09", "22", "27", "17", "08", "01", "09"]