抽象元组函数中的参数名称

Question

与 No argument names in abstract declaration? 相关，您将如何使用 C# 样式的元组参数执行此操作？所以如果我想要

abstract member createEmployee : (string * string) -> Employee

我如何才能传达它是否应该

1-   member this.createEmployee(firstName, lastName) = ...
2-   member this.createEmployee(lastName, firstName) = ...

用例：在 F# 中创建要从 C# 使用的接口。

Answer 1

我认为最简单的方法是这样：

type FirstName = FirstName of string
type LastName  = LastName of string

...

abstract member createEmployee : (FirstName * LastName) -> Employee

备注：

你可能希望它是

abstract member createEmployee : FirstName * LastName -> Employee

相反，因为存在细微差别 ;)

Answer 2

有两种方法可以做到这一点：

使用 MSDN

中所述的命名参数

member this.createEmployee(firstName: string, lastName: string) = ...

// external code
MyClass.createEmployee(firstName = "John", lastName = "Smith")
MyClass.createEmployee(lastName = "Smith", firstName = "John")

让您的 class 成员接受结构作为参数：

type EmployeeName =
   struct 
      val firstName: string
      val lastName: string
   end 

member this.createEmployee2(employeeName: EmployeeName) = ...

// external code
MyClass.createEmployee2 {firstName = "John"; lastName = "Smith"}
MyClass.createEmployee2 {lastName = "Smith"; firstName = "John"}

选择权在你；前者允许可选参数（考虑 middleName 或 salutation），而后者允许将结构存储在一起（例如，如果您需要进一步处理它）。

Answer 3

abstract createEmployee: firstName:string * lastName:string -> Employee

编译以创建 C# 调用语义，名称出现在 Visual Studio 2013 年的 C# 和 F# intellisense 中。

抽象元组函数中的参数名称

Parameter names in abstract tupled function

f#

c#-to-f#

备注：