Java

Question

我只是编码方面的初学者，并试图用几个 classes 制作我的第一个项目，这是一个刽子手游戏。我知道这里有很多关于该主题的线程，但无法找到适用于 StringBuilder 的解决方案。我坚持在单词中捕捉多个字母。任何人都可以帮忙吗？有问题的方法是 checkAnswer，如下所示：

public void checkAnswer (){
    if (logic.line.indexOf(answer)!= -1){
    System.out.println ("You are right! The letter " + answer + " exists");
    StringBuilder guessedChar = new StringBuilder(logic.newLine);
    guessedChar.setCharAt(logic.line.indexOf(answer), answer);
    lettersGuessed = answer +lettersGuessed;
            score = score + 1;
            System.out.println("Letters guessed: " + lettersGuessed);
            System.out.println("Letters missed: " + lettersMissed);
            System.out.println("Your score is:" + score);
   logic.newLine = guessedChar.toString();
    System.out.println(logic.newLine);
        }}

完整代码如下：主要 class public class 主要 {

public static void main(String[] args) throws Exception {
    Logic act = new Logic();
    Game game = new Game();
    act.getListOfMovies();
    act.CodedLine();
    do { game.input();
    game.checkCondition();
            game.checkAnswer();
            game.checkScore();
    } while (game.lettersGuessed.length() != act.line.length() && game.score!= -10);
}}

Class逻辑

public class Logic {
static String line;
static String newLine;
public String[] listOfMovies;
public Scanner fileScanner;

public Logic() {
}

public String getListOfMovies() throws Exception {
    File fileWithMovies = new File("MoviesList.txt");//file access
    Scanner fileScanner = new Scanner(fileWithMovies);//file scan
    while (fileScanner.hasNext()) { // while there is a next line
        line = fileScanner.nextLine();
        String[] listOfMovies = new String[24];  //introduce array
        for (int i = 0; i < listOfMovies.length; i++) { //
            listOfMovies[i] = fileScanner.nextLine();
        } 
        int random = (int) (Math.random() * listOfMovies.length);  //get random number
        for (int i = 0; i < line.length(); i++) {             //get random movie
            if (Character.isLetter(line.charAt(i))) {
                line = listOfMovies[random];
                System.out.println(line);
            }
            return line;
        }
        return line;
    }return line;
}



public String CodedLine() {
    newLine = line.replaceAll("[a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z]", "_");
    System.out.println(newLine);
    return newLine;
}}

Class 游戏

public class Game {
char answer;
Logic logic = new Logic();
String lettersGuessed = " ";
String lettersMissed = " ";
int score = 0;


public char input () {
    Scanner inputScanner = new Scanner(System.in);
    System.out.println("Type in your guess");
    answer = inputScanner.next().charAt(0);
    System.out.println("Your guess: " + answer);
    return answer;
    }
public void checkCondition (){
if (logic.line.indexOf(answer)==-1){
    System.out.println("You are wrong. The letter " + answer + " does not exist");
    lettersMissed = answer + lettersMissed;
    score = score - 1;
    System.out.println("Letters guessed: " + lettersGuessed);
    System.out.println("Letters missed: " + lettersMissed);
    System.out.println("Your score is:" + score);
}}

public void checkAnswer (){
    if (logic.line.indexOf(answer)!= -1){
    System.out.println ("You are right! The letter " + answer + " exists");
    StringBuilder guessedChar = new StringBuilder(logic.newLine);
    guessedChar.setCharAt(logic.line.indexOf(answer), answer);
    lettersGuessed = answer +lettersGuessed;
            score = score + 1;
            System.out.println("Letters guessed: " + lettersGuessed);
            System.out.println("Letters missed: " + lettersMissed);
            System.out.println("Your score is:" + score);
   logic.newLine = guessedChar.toString();
    System.out.println(logic.newLine);
        }}

public void checkScore (){
    if (score == -10) {
        System.out.println("The game is over! You lost..."); }}}

Answer 1

不会为你解决问题，不是这个网站的目的，而是建议：

check this method - 基本上你告诉它 indexOf 应该从哪里开始搜索。首先你从 0 开始，然后如果你找到一个结果，你从 foundResultIndex + 1 开始，把它全部放在一个循环中，瞧。

word: batman, guess: a

int startAt = 0;

int foundResultIndex = "batman".indexOf('a', startAt) // 1

startAt = foundResultIndex + 1;

foundResultIndex = "batman".indexOf('a', startAt) // 4

...

不要在程序中保留太多状态，尤其是像 Logic class 中那样的静态状态。你的 getListOfMovies 是一个完美的例子，你已经返回了一个结果，为什么要将它保存在一些 line 变量中？请改用返回的结果。
replaceAll 很有趣，改用这个 line.replaceAll("[a-z]", "_");

Answer 2

//Create list for index 
ArrayList<Integer>answerIndexList=new ArrayList<Integer>();


//get char index
for (int i=0;i<logic.line.length();i++){
    if(logic.line.charAt(i) == answer){
        answerIndexList.add(i);
     }
}


//replace index with answer
for(int i=0;i<answerIndexList.size();i++){

    guessedChar.setCharAt(answerIndexList.get(i), answer);
}

logic.newLine = guessedChar.toString();

Java - 使用 StringBuilder 的 Hangman 游戏。捕捉一个单词中的多个字母

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