如何实现电压降的计算？

Question

我对此很陌生，所以试着做笔记。提前致谢。编写一个程序来计算最多 5 个电阻器的电路的并联和串联电路。该计划必须：提示电路中电阻的个数提示用户select串联或并联对于串联电路，输出将是总电阻和每个电阻两端的电压降。对于并联电路，输出将是总电阻和通过每个电阻的电流。

series circuit calculation:
total resistance= r1 +r2+rn
I=v/r_total
voltage drop in r1 = r1*I and so on until r5.
i'm trying to do the calculations for voltage drop using an array but its not working and i'm not sure why.

i'm getting an error and i'm not sure why



    #include <iostream>
    #include <string>
    #include <cmath>

    using namespace std;

    string circuitType(string x)
    {
        string P, S; //Parallel circuit (p) and series circuit (s)

        while (x!="P" && x!="S")
        {

        if (x=="P")
            {
            cout<<"     Parallel Circuit Calculator\n\n";
            }
        else if(x=="S")
            {
            cout<<"     Series Circuit Calculator\n\n";
            }
        else 
            {
            cout << "Please Enter the type of circuit (P/S):";
            cin >>x;
            }
        }
        return(x);
    }

    int main()
    {

        string userChoice = "Yes";
        string userans ;
        string P, S; //Parallel circuit (p) and series circuit (s)

        while (userChoice == "Yes")
        {
        double R [5];//[5] = {1, 2,3,4,5};//an array of Resistors 1 to 5

        double V, I; //Voltage and Current

        double e_R= 0.0; //Equivalent Resistance

        double r_T= 0.0; //Total resistance

        double v_D= 0.0; //Voltage drop

        cout <<"                Welcome to Circuit Calculator \n";
        cout <<"\n";

        cout <<"\n (Main) Please Enter the type of circuit (P/S):";
        cin >>userans;
        userans = circuitType(userans);

    if (userans == "S")
        {

    // a fuction for the prompt the user to enter resistance values

        cout<<"Enter the values for Resistors 1 to 5: \n";
        for(int i=0; i<=5;i++) 

    //implementing that i has a value more than 0and less than or equal                     
 to 5

            {
           cout<<"Enter R"<<i+1<<" = ";//output of Resistance values 
           from 1 to 5
           cin>>R[i];   
            }       
    //calculating Equivalent Resistance

       for (int i=0; i<=5;i++)
       r_T+= R[i];
       cout<< "The Total Resistance is "<<r_T<<"ohms.\n"; 

    // prompting the user to enter voltage value

        cout<< "enter V: ";
        cin >> V;

    //calculating current

        I = V/(r_T);
        cout<<"\n current = "<<I;

    // voltage drop at Resistors.

        for (int i=0; i<=5;i++) 

    //error 1 [Error] invalid types 'double[int]' for array subscript

        v_D[i] *= (R[i],I);

//  2[Error] name lookup of 'i' changed for ISO 'for' scoping [- 
    fpermissive]
//  3[Note] (if you use '-fpermissive' G++ will accept your code)
//  4[Error] invalid types 'double[int]' for array subscript

    cout << "The voltage drop at R"<<i <<"=" <<v_D[i]++<<"V\n";

        }

    //if resistance connected in parallel       
    //calculating equivalent resistance
    //eR=1/resistance;
    //printing current accross all resistance
    //I=voltage/resistance;

    //when circuit is connected in series   

        cout <<"Do you want to run calculator again?(Yes/No)\n";
        cin >>userChoice;
        cout <<"\n\n";
    }
        return 0;
    }

Answer 1

我相信你忘了将 v_D 声明为数组。

您将变量声明为双精度（不是数组）： double v_D= 0.0;

然而，在代码中，您将其视为一个数组： v_D[i] 和 v_D[i]++.

要审核，要申报可能要：

static const unsigned int MAX_RESISTORS = 5;
double Resistors[MAX_RESISTORS];
double voltage_drops[MAX_RESISTORS];

我建议暂时离开您的代码，然后回来进行 objective 检查。 :-)

如何实现电压降的计算？

how to implement the calculation of voltage drop?

c++

dev-c++