转换 R 数据框中的区间外连接 SQL

Question

我之前在 Python 遇到过同样的问题：我想在 R 中完成。

我正在将 Oracle SQL 外部间隔连接转换为 R。下面是 Oracle SQL:

WITH df_interval AS
          (SELECT '1' id,
                     'AAA' interval,
                     1000 begin,
                     2000 end
              FROM DUAL
            UNION ALL
            SELECT '1' id,
                     'BBB' intrvl,
                     2100 begin,
                     3000 end
              FROM DUAL
            UNION ALL
            SELECT '2' id,
                     'CCC' intrvl,
                     3100 begin,
                     4000 end
              FROM DUAL
            UNION ALL
            SELECT '2' id,
                     'DDD' intrvl,
                     4100 begin,
                     5000 end
              FROM DUAL),
      df_point AS
          (SELECT '1' id, 'X1' point, 1100 mid FROM DUAL
            UNION ALL
            SELECT '1' id, 'X2' point, 2050 mid FROM DUAL
            UNION ALL
            SELECT '1' id, 'X3' point, 3200 mid FROM DUAL
            UNION ALL
            SELECT '2' id, 'X4' point, 4200 mid FROM DUAL
            UNION ALL
            SELECT '2' id, 'X5' point, 5500 mid FROM DUAL)
SELECT pt.id,
         point,
         mid,
         interval
  FROM df_interval it RIGHT OUTER JOIN df_point pt ON pt.id = it.id AND pt.mid BETWEEN it.begin AND it.end

我希望这样的结果：

  ID point   mid interval
0  1    X1  1100      AAA
1  1    X2  2050      NaN
2  1    X3  3200      NaN
3  2    X4  4200      DDD
4  2    X5  5500      NaN

感谢任何人可以帮助我吗？

Answer 1

这是一个使用 data.table 包的选项：

library(data.table)
setDT(df_interval)
setDT(df_point)
df_interval[df_point, on=.(id, begin<=mid, end>=mid),
    .(ID=id, point=i.point, mid=i.mid, interval=x.interval)]

输出：

   ID point  mid interval
1:  1    X1 1100      AAA
2:  1    X2 2050     <NA>
3:  1    X3 3200     <NA>
4:  2    X4 4200      DDD
5:  2    X5 5500     <NA>

数据：

df_interval <- data.frame(id=c(1,1,2,2), 
    interval=c('AAA','BBB','CCC','DDD'),
    begin=c(1000,2100,3100,4100),
    end=c(2000,3000,4000,5000))
df_point <- data.frame(id=c(1,1,1,2,2),
    point=c('X1','X2','X3','X4','X5'),
    mid=c(1100,2050,3200,4200,5500))

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